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mars1129 [50]
3 years ago
11

A laboratory assistant needs to prepare 35. 2 liters of hydrogen at 25. 0°C and 101. 3 kilopascals. This is the equation for the

reaction: 2HCl Ca → H2 CaCl2 What volume of 2. 3 M hydrochloric acid is required to produce this much gas? Use the ideal gas resource. A. 0. 625 L B. 0. 876 L C. 1. 18 L D. 1. 25 L.
Chemistry
1 answer:
KengaRu [80]3 years ago
4 0

The ideal gas equation states that the volume is directly proportional to the moles and temperature but inversely to pressure. The volume required is 1.25 L.

<h3>What is the ideal gas equation?</h3>

An ideal gas is the hypothetical gas equation that depicts the relation of the temperature, pressure, volume and moles of the substance of the gas.  It is given as,

\rm PV = nRT

Where,

The pressure of hydrogen gas (P) = 1 atm

The volume of hydrogen gas (V) = 35.2L

The temperature of hydrogen gas (T) = 298 K

Gas constant (R) = 0.0821 L. atm. per mol. per K

Substituting values in the equation,

\begin{aligned}\rm n &= \rm \dfrac{PV}{RT}\\\\&= \dfrac{35.2\times 1}{0.0821\times 298}\\\\&= 1.438\;\rm moles\end{aligned}

The balanced chemical reaction can be shown as,

\rm 2HCl + Ca \rightarrow H_{2} + CaCl_{2}

From the reaction, it can be deduced that, 2 moles of hydrochloric acid = 1 mole of hydrogen gas.

So, 1.438 moles of hydrogen molecules will produce 2.876 moles of HCl.

The volume of HCl can be calculated as,

\begin{aligned}\rm Volume &= \rm \dfrac{moles}{Molarity}\\\\&= \dfrac{2.876}{2.3}\\\\&= 1.25\end{aligned}

Therefore, option D. 1.25 L is the volume of the hydrochloric acid.

Learn more about volume and molarity here:

brainly.com/question/11150331

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Explanation:

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An experiment with 55 co takes 47.5 hours. at the end of the experiment, 1.90 ng of 55-co remains. if the half-life is 18.0 hour
Andru [333]

Answer:

\boxed{\text{10.7 ng}}

Explanation:

Let A₀ = the original amount of ⁵⁵Co .

The amount remaining after one half-life is ½A₀.

After two half-lives, the amount remaining is ½ ×½A₀ = (½)²A₀.

After three half-lives, the amount remaining is ½ ×(½)²A₀ = (½)³A₀.

The general formula for the amount remaining is:

A =A₀(½)ⁿ

where n is the number of half-lives

n = t/t_½

Data:

   A = 1.90 ng

    t = 45 h

t_½ = 18.0 h

Calculation:

(a) Calculate n

n = 45/18.0 = 2.5

(b) Calculate A

1.90 = A₀ × (½)^2.5

1.90 = A₀ × 0.178

A₀ = 1.90/0.178 = 10.7 ng

The original mass of ⁵⁵Co was \boxed{\text{10.7 ng}}.

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