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blsea [12.9K]
2 years ago
7

How is the capacitance of a capacitor related to the charge stored on the capacitor and the potential difference across the capa

citor?.
Physics
1 answer:
tatuchka [14]2 years ago
6 0

Answer:

Capacitance is the ratio of the charge to the potential difference. How is the charge stored on a capacitor related to the capacitance of the capacitor and the potential difference across the capacitor? The charge equals the product of the capacitance and the potential difference.

Explanation:

Hope this helps

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Help me solve this please
Leto [7]
Since it's a projectile being launched the only force acting upon it is gravity, since the object is in free fall once it's launched

so to calculate time you'd utilize the general formula of
xf = xi + vxi(t) + \frac{1}{2} (a) {t}^{2}
and then solve using time and make it into the y axis, so change the x's to y's, which will change a to g.
since Vyi is always usually 0, you can drop that out of this equation so the formula to find time would be
t =  \sqrt{ \frac{2(y)}{g} }
So you'll plug in and it'll be
t =  \sqrt{ \frac{2( - 49m)}{ - 9.81 \frac{m}{s {}^{2} } } }
to find the maximum height you'll have to do some trigonometry to solve it.
To make it easier draw a triangle
put the 60° mark as shown in the picture.
Then you'll need to find the hypotenuse or horizontal to find the vertical
So the hypotenuse would be the 113m/s
so then you'll use
\ \sin( 60) = ( \frac{o}{h})

plug in the numbers
113( \ \sin (60) ) = o
now that you have the vertical

use the formula
{vf}^{2}  =  {vi}^{2}  + 2gd
solve for d which will give you the hypotenuse
d = { (-vertical \frac{m}{s} )}^{2}  \div 2( - 9.81 \frac{m}{ {s}^{2} } )
The "vertical" is what you found in the previous step.
Vf^2 is equal to 0 so you can just drop that number out since it's 0
then once you have that then youre not done yet
since you're on a cliff of 49 m you'll have to add 49m to the previous answer that you found d to find the maximum height.

I hope this helps!

6 0
3 years ago
A cyclist rides at 30 kilometres per hour. How far will he travel in 2 hours?
GarryVolchara [31]

Answer:

a

Explanation:

3 0
2 years ago
Which statement is TRUE about the factors affecting physical fitness?A.
seropon [69]

Answer:

D

Explanation:

6 0
3 years ago
An observer in frame S sees lightning simultaneously strike two points 100 m apart. The first strike occurs at xx1 = yy1 = zz1 =
Veseljchak [2.6K]

Answer:

a) 0, = -0.33 us

b) 140m

c) No, The event are not simultaneous i.e they did not occur at the same time, the second even (-0.33 usec) occurs 0.33 usec earlier than the first event.

Explanation:

a)

the lorentz factor expression is written as;

y = 1₀ / √(1 - (v²/c²))

where v  is the relative speed of an observer and c is the speed of light

so we were given that relative speed to be o.7c

therefore

y = 1 / √(1 - ((0.7c)² / c²))

y = 1 / √(1 - (0.49c² / c²))

y = 1 / √(1 - 0.49)

y = 1 / 0.7141

y = 1.4

1 - the coordinates  of the first event, the s' frame of reference is,

x1 ' = y(x1 - vt1) = 0

y1 ' = y1, z1' = z1 and

t1 ' = y [t1 - v/c²x1]

= 0

2 - the coordinates of the second event, the s ' frame of reference is'

x2 ' = y(x2-vt2)

= 1.4(100m - 0)

= 140m

y2 ' = y2, z2 ' = z2

t2 ' = y [ t2 - v/c²x2 ]

= 1.4 [ 0 - 0.7c/c²(100) ]

using speed of light c as 3*10^8

1.4 [ 0 - (0.7*3*10^8) / (3*10^8)²(100) ]

= -0.33 us

b)

distance between

delltaX' = X2' - X1'

= 140m - 0

= 140m

c)

No, The event are not simultaneous i.e they did not occur at the same time.

the second even (-0.33 us) occurs 0.33 us earlier than the first event.

4 0
3 years ago
Does changing position of charges change the magnitude
hodyreva [135]

Answer:

No, they will not change.

Explanation:

7 0
3 years ago
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