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blsea [12.9K]
2 years ago
7

How is the capacitance of a capacitor related to the charge stored on the capacitor and the potential difference across the capa

citor?.
Physics
1 answer:
tatuchka [14]2 years ago
6 0

Answer:

Capacitance is the ratio of the charge to the potential difference. How is the charge stored on a capacitor related to the capacitance of the capacitor and the potential difference across the capacitor? The charge equals the product of the capacitance and the potential difference.

Explanation:

Hope this helps

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An occupant of a car has a chance of surviving a crash if the deceleration during the crash is not more then 30 g. Calculate the
sweet [91]

Answer:

20,850 N

Explanation:

We can solve the problem by using second Newton's Law:

F=ma

where

F is the force

m is the mass

a is the acceleration

In this problem, we have:

m = 70 kg is the mass

a=-30 g=-30 (9.8 m/s^2)=-294 m/s^2 is the acceleration (which is negative, because it is a deceleration)

So, we can use the equation above to find the force:

F=(70 kg)(-294 m/s^2)=-20580 N

and the negative sign simply means that the force is in the opposite direction to the motion.

5 0
3 years ago
Green light (λ = 518 nm) strikes a single slit at normal incidence. What width slit will produce a central maximum that is 3.00
MariettaO [177]

Answer:

6.9066 × 10⁻⁵ m

Explanation:

For constructive interference, the expression is:

d\times sin\theta=m\times \lambda

Where, m = 1, 2, .....

d is the distance between the slits.

The formula can be written as:

sin\theta=\frac {\lambda}{d}\times m ....1

The location of the bright fringe is determined by :

y=L\times tan\theta

Where, L is the distance between the slit and the screen.

For small angle , sin\theta=tan\theta

So,  

Formula becomes:

y=L\times sin\theta

Using 1, we get:

y=L\times \frac {\lambda}{d}\times m

Thus, the distance between the central maximum is 3.00 cm

First bright fringe , m = 1 occur at 3.00 / 2 = 1.50 cm

Since,

1 cm = 0.01 m

y = 0.0150 m

Given L = 2.00 m

λ = 518 nm

Since, 1 nm = 10⁻⁹ m

So,

λ = 518 × 10⁻⁹ m

Applying the formula as:

0.0150\ m=2.00\ m\times \frac {518\times 10^{-9}\ m}{d}\times 1

<u>⇒ d, distance between the slits = 6.9066 × 10⁻⁵ m</u>

7 0
3 years ago
We can model the human back as a pivoted rod?
3241004551 [841]

Answer:

So the answer is yes, we can the back be shaped like a spinning rod

spinal column that is approximated by a long and narrow rod,

Explanation:

The bone system of the body is very well modeled in physics, the back has a spinal column that is approximated by a long and narrow rod, this rod is fixed in the lower part to the coccyx and has a weight in the upper part (head), this rod has longitudinal vertical movement and twisting movement around the lower part of the bar.

So the answer is yes, we can the back be shaped like a spinning rod

7 0
3 years ago
Planet A has a mass of 2.25 x 1020 kg, while planet B has a
denis23 [38]

The gravitational attraction between two planets is  4905.95 N

<h3>What is gravitational attraction?</h3>

When two objects with masses are placed at a distance, there will an attractive force acting between them.

According to the Newton's law of gravitation, gravitational force is

F = Gm₁m₂ /r²

where r is the distance between the masses m₁ and m₂ and  G is the gravitational constant G = 6.67 x 10⁻¹¹ N-m²/kg²

Substitute the values into the expression, we get

F =  6.67 x 10⁻¹¹ x  2.25 x 10²⁰ x 6.20 x 10¹⁸ / (435,500 x 1000)²

F= 4905.95 N

Thus, the gravitational attraction between two planets is  4905.95 N.

Learn more about gravitational attraction.

brainly.com/question/19822389

#SPJ2

6 0
2 years ago
Read 2 more answers
1. Name two ways of applying forces ?​
Anna007 [38]

Answer: A force can be applied to another object by a direct push, pull, or drag.

Explanation:

4 0
2 years ago
Read 2 more answers
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