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blsea [12.9K]
2 years ago
7

How is the capacitance of a capacitor related to the charge stored on the capacitor and the potential difference across the capa

citor?.
Physics
1 answer:
tatuchka [14]2 years ago
6 0

Answer:

Capacitance is the ratio of the charge to the potential difference. How is the charge stored on a capacitor related to the capacitance of the capacitor and the potential difference across the capacitor? The charge equals the product of the capacitance and the potential difference.

Explanation:

Hope this helps

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he Volume in an experiment is changed (in mL) is 200, 100, 50, 25, 12.5 and we measured the pressure (in atm) is 0.1000, 0.2000,
s344n2d4d5 [400]

Answer: Slope = - 1000.

Explanation:

The line of best fit of the graph will be linear.

The general linear equation can be expressed as;

Y = MX + C

Where the Y variable represents the volume in the experiment as dependent variable and the X represent the pressure as independent variable.

The equation can be rewritten as:

V = MP + C

Where C is the intercept.

Given that

V = 200, 100, 50, 25, 12.5 and

Pressure P = 0.1000, 0.2000, 0.4000, 0.8000, 1.6000

The slope M can be calculated by using the formula

M = (V2 - V1)/ (P2 - P1)

Where V1 = 200, V2 = 100, P1 = 0.1, P2 = 0.2

Substitute all the parameters into the formula

M =( 100 - 200)/ ( 0.2 - 0.1 )

M = -100/0.1

Slope M = - 1000

7 0
3 years ago
A car increases its speed from 20km/hr to 50km/hr in seconds. Its acceleration is _____.
mash [69]

Answer:

Option D

0.83 m/s2

Explanation:

Time is assumed as 10 seconds

First, convert the speeds from km/h to m/s

20 km/h\times \frac {1000 m}{3600 s}=5.555555556 m/s \approx 5.56 m/s

50 km/h\times \frac {1000 m}{3600 s}=13.88888889  m/s \approx 13.89 m/s

Acceleration, a=\frac {v-u}{t} where u and v are the initial and final velocities respectively, t is the time taken to accelerate.

Substituting 13.89 m/s for v, 5.56 m/s for u and 10 s for t then

a=\frac {13.89-5.56}{10}=0.8333333 m/s^{2}\approx 0.83 m/s^{2}

7 0
3 years ago
The percent by which the fundamental frequency changed if the tension is increased by 30 percent is ? a)-20.04% b)-40.12% c)-30%
nika2105 [10]

Answer:

Percentage increase in the fundamental frequency is

d)-14.02%

Explanation:

As we know that fundamental frequency of the wave in string is given as

f_o = \frac{1}{2L}\sqrt{\frac{T}{\mu}}

now it is given that tension is increased by 30%

so here we will have

T' = T(1 + 0.30)

T' = 1.30T

now new value of fundamental frequency is given as

f_o' = \frac{1}{2L}\sqrt{\frac{1.30T}{\mu}}

now we have

f_o' = \sqrt{1.3}f_o

so here percentage change in the fundamental frequency is given as

change = \frac{f_o' - f_o}{f_o} \times 100

% change = 14.02%

3 0
2 years ago
A stone is dropped from top of a tower. If it takes 6 sec to hit the ground, find the height of tower and velocity with which th
-Dominant- [34]

Answer:

Explanation:

s = ut+ 0.5at²

u = 0

t = 6

a = 9.81

s = 0 + 0.5 * 9.81 * 36 = 176.58 m

v = u + at

v = 9.81* 36 = 353 m/s

4 0
2 years ago
In projectile mtion, what is the y-component of the initial velocity? if V= Vi = 100 m/s and the angle with horizontal axis Θ =
Damm [24]

Answer:

hence the y - component of the velocity is 50m/s

4 0
3 years ago
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