Answer:
a) 2.4 mm
b) 1.2 mm
c) 1.2 mm
Explanation:
To find the widths of the maxima you use the diffraction condition for destructive interference, given by the following formula:
![m\lambda=asin\theta](https://tex.z-dn.net/?f=m%5Clambda%3Dasin%5Ctheta)
a: width of the slit
λ: wavelength
m: order of the minimum
for little angles you have:
![y=\frac{m\lambda D}{a}](https://tex.z-dn.net/?f=y%3D%5Cfrac%7Bm%5Clambda%20D%7D%7Ba%7D)
y: height of the mth minimum
a) the width of the central maximum is 2*y for m=1:
![w=2y_1=2\frac{1(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}=2.4*10^{-3}m=2.4mm](https://tex.z-dn.net/?f=w%3D2y_1%3D2%5Cfrac%7B1%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%3D2.4%2A10%5E%7B-3%7Dm%3D2.4mm)
b) the width of first maximum is y2-y1:
![w=y_2-y_1=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[2-1]=1.2mm](https://tex.z-dn.net/?f=w%3Dy_2-y_1%3D%5Cfrac%7B%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%5B2-1%5D%3D1.2mm)
c) and for the second maximum:
![w=y_3-y_2=\frac{(500*10^{-9}m)(1.2m)}{0.50*10^{-3}m}[3-2]=1.2mm](https://tex.z-dn.net/?f=w%3Dy_3-y_2%3D%5Cfrac%7B%28500%2A10%5E%7B-9%7Dm%29%281.2m%29%7D%7B0.50%2A10%5E%7B-3%7Dm%7D%5B3-2%5D%3D1.2mm)
"he force exerted by the car is more than the force exerted b y the snowball" is the one among the following that can be said <span>about the magnitude of the forces exerted by the snowball and the car. The correct option among all the options that are given in the question is the first option or option "A". I hope it helps you.</span>
Answer:v=3.08 m/s
Explanation:
Given
mass of student ![m=21 kg](https://tex.z-dn.net/?f=m%3D21%20kg)
distance moved ![d=10 m](https://tex.z-dn.net/?f=d%3D10%20m)
Force applied ![F=10 N](https://tex.z-dn.net/?f=F%3D10%20N)
acceleration of system during application of force is a
![a=\frac{F}{m}=\frac{10}{21}=0.476 m/s^2](https://tex.z-dn.net/?f=a%3D%5Cfrac%7BF%7D%7Bm%7D%3D%5Cfrac%7B10%7D%7B21%7D%3D0.476%20m%2Fs%5E2)
using ![v^2-u^2=2 as](https://tex.z-dn.net/?f=v%5E2-u%5E2%3D2%20as)
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
![v^2-0=2\times 0.476\times 10](https://tex.z-dn.net/?f=v%5E2-0%3D2%5Ctimes%200.476%5Ctimes%2010)
![v=\sqrt{9.52}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B9.52%7D)
![v=3.08 m/s](https://tex.z-dn.net/?f=v%3D3.08%20m%2Fs)
I don’t know, which statement ahh I see white screen lol
That's true. The mass of your body is like the money
in your pocket. It doesn't change, no matter where you
take it.