Answer:
The answer is
<h2>16.8 mL</h2>
Explanation:
The volume of a substance when given the density and mass can be found by using the formula

From the question
mass of object = 52.9 g
density = 3.14 g/mL
The volume of the object is

We have the final answer as
<h3>16.8 mL</h3>
Hope this helps you
Answer:
490
98 for 1 mole, Hence for 5 moles 5 X 98 =490.
Explanation:
Brainliest please?
Answer: 373 mL
Explanation:
Since there is no change in pressure, the formula: V / T = V / T can be used.
However, you must first convert the temperatures to Kelvin by adding 273 to them:
(19 + 273) = 292K and (90 + 273) = 363K.
Now, plug in: V / 292 = 464 / 363 → V = 373 mL :)
Answer : The oxidation state of Mg in Mg(s) is (0).
Explanation :
Oxidation number or oxidation state : It represent the number of electrons lost or gained by the atoms of an element in a compound.
Oxidation numbers are generally written with the sign (+) and (-) first and then the magnitude.
Rules for Oxidation Numbers are :
The oxidation number of a free element is always zero.
The oxidation number of a monatomic ion equals the charge of the ion.
The oxidation number of Hydrogen (H) is +1, but it is -1 in when combined with less electronegative elements.
The oxidation number of oxygen (O) in compounds is usually -2.
The oxidation number of a Group 17 element in a binary compound is -1.
The sum of the oxidation numbers of all of the atoms in a neutral compound is zero.
The sum of the oxidation numbers in a polyatomic ion is equal to the charge of the ion.
The given chemical reaction is:

In the given reaction, the oxidation state of Mg in Mg(s) is (0) because it is a free element and the oxidation state of Mg in
is (+2).
Hence, the oxidation state of Mg in Mg(s) is (0).
Answer: m = 50 g ZnSO4
Explanation: First is convert the moles of Zn to the moles of ZnSO4 by having their mole ratio which is 2:2 based from the balanced equation. Next is convert the moles of ZnSO4 to mass using its molar mass.
0.311 mole Zn x 2 moles ZnSO4 / 2 moles Zn
= 0.311 moles ZnSO4
0.311 moles ZnSO4 x 161 g ZnSO4 / 1 mole ZnSO4
= 50 ZnSO4