You can find it by adding the standard atomic masses of the constituent atoms.
Answer:
1) 18.91 mL
2) 2.35 %
Explanation:
1. The volume of base that was required is equal to the <em>difference between the reading at the end of the titration and the reading at the beginning</em>:
- V = 20.95 mL - 2.04 mL = 18.91 mL
2. The mass percent can be written as:
- Mass Percent = Mass solute / Total mass * 100%
For this problem:
We<u> input the data and calculate the mass percent</u>:
- % mass = 2.28/96.92 * 100% = 2.35 %