Answer:
Rate of the reaction is 0.2593 M/s
-0.5186 M/s is the rate of the loss of ozone.
Explanation:
The rate of the reaction is defined as change in any one of the concentration of reactant or product per unit time.
Rate of formation of oxygen :
Rate of the reaction(R) =
Rate of formation of oxygen=3 × (R)
Rate of the reaction(R):
Rate of the reaction is 0.2593 M/s
Rate of disappearance of the ozone:
-0.5186 M/s is the rate of the loss of ozone.
The frequency of the radiation is equal to Hertz.
<u>Given the following data:</u>
To find the frequency of this radiation, we would use the Planck-Einstein equation.
Mathematically, the Planck-Einstein relation is given by the formula:
<u>Where:</u>
Substituting the given parameters into the formula, we have;
Frequency, F = Hertz
Read more: brainly.com/question/16901506
Answer:
The answer is 3-Phenylpropanoic acid (see attached structure)
Explanation:
From spectral data:
3005 cm-1 ⇒ carboxylic acid (broad band)
1670 cm-1 ⇒ C=C
1603 cm-1 ⇒ Aromatic C-C bond
H NMR frequency at 2.6 ppm, singlet, ⇒ OH with no surrounding protons, possible deshielding (clearer investigation of spectrum would be expedient).
Hence, our C9H10O2 compound has an aromatic ring and carboxylic acid group attached to it.
