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lbvjy [14]
3 years ago
7

(1) Some years ago, a crucial experimental error was made during the work-up of the reaction. Instead of adding the reaction mix

ture to the cold acid solution, the inverse addition was carried out. What do you think happened when the acid solution was added to the reaction mixture
Chemistry
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

Salts will be formed and the pH of the new mixture will fall.

Explanation:

What should be: The reaction mixture should be added to the cold acid solution.

The error: Cold acid solution was added to the reaction mixture.

What happens with this?

The neutralization of a solution creates salts. The combination of positive and negative ions in the reaction also forms water. Assuming the pH of the reaction mixture was neutral before the addition of the acid, after the addition of the acid solution the pH will drop. Recall that a neutral solution has a pH of 7. So the pH of this new solution will drop to less than 7 because of the addition of an acid.

If the required procedure for the chemical process was followed, the reaction mixture added to the cold acid would have resulted in a stronger base solution. In other words, the pH of the new solution would be higher.

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The osmolarity of a 1-l bottle of 5% dextrose solution is _____ mosm/l.
Pachacha [2.7K]
M(dextrose) = 50 g.
V(solution) = 1 L.
n(dextrose) = 50 g ÷ 180 g/mol.
n(dextrose) = 0,27 mol.
Osmotic concentration (osmolarity)<span> is a measure of how many </span><span>osmoles of particles of solute</span><span> it contains </span>per liter.
The osmolarity = n(dextrose) ÷ V(solution).
The osmolarity = 0,27 mol ÷ 1 L.
The osmolarity = 0,27 mol/L · 1000 mmol/m.
The osmolarity (dextrose) = 270 mosm/L.
The osmolarity (dextrose monohydrate) = 50 g÷197 g/mol·1000 =254mosm/L
7 0
3 years ago
Read 2 more answers
Is the element Na a metal or non metal
Bond [772]

Answer:

Metal

Explanation:

Na or sodium though soft... it is a metal...

8 0
3 years ago
3.) 2.46 grams of Cu(NO3)2 would contain how many formula units?
RUDIKE [14]

Answer:

7.90×10²¹ formula units

Explanation:

From the question given above, the following data were obtained:

Mass of Cu(NO₃)₂ = 2.46 g

Formula units of Cu(NO₃)₂ =?

From Avogadro's hypothesis,

1 mole of Cu(NO₃)₂ = 6.02×10²³ formula units

Next, we shall determine the mass of 1 mole of Cu(NO₃)₂. This can be obtained as follow:

1 mole of Cu(NO₃)₂ = 63.5 + 2[14 + (3×16)]

= 63.5 + 2[14 + 48]

= 63.5 + 2[62]

= 63.5 + 124

= 187.5 g

Thus,

187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units

Finally, we shall determine the formula units contained in 2.46 g of Cu(NO₃)₂. This can be obtained as follow:

187.5 g of Cu(NO₃)₂ = 6.02×10²³ formula units.

Therefore,

2.46 g of Cu(NO₃)₂ =

(2.46 × 6.02×10²³)/187.5

= 7.90×10²¹ formula units

Thus, 2.46 g of Cu(NO₃)₂ contains 7.90×10²¹ formula units

7 0
3 years ago
Fill in the coefficients that will balance the following reaction: <br> Zn +Fe(NO3)2---ZnNO3+Fe
kakasveta [241]
In order to balance reactions, the number of each element must be the same on the left and right side. If I have 3 of element X on one side, I must have 3 of element X on the other side. That being said:

Zn + Fe(NO3)2 —> ZnNO3 + Fe

I have two NO3 groups on the left, so I will add a coefficient of 2 in front of the compound which has an NO3 group on the right side.

Zn + Fe(NO3)2 —> 2ZnNO3 + Fe

Since I now have 2 Zn’s on the right, and only 1 on the left, I will add a coefficient of 2 in front of Zn on the left.

2Zn + Fe(NO3)2 —> 2ZnNO3 + Fe

Lets check:
Zn: 2 right, 2 left (correct)
Fe: 1 right, 1 left (correct)
NO3 groups: 2 right, 2 left

We have successfully balanced the equation. :)
7 0
3 years ago
Zinc(II) sulfide reacts with oxygen according to the reaction: A reaction mixture initially contains 3.0 mol ZnS and 2.0 mol O2.
tiny-mole [99]

Answer:

Excess reagent is the ZnS. After the reaction is complete, 1.67 moles of sulfide remain.

Explanation:

This is the reaction to work with:

2ZnS + 3O₂  →  2ZnO + 2SO₂

Limiting reagent is the oxygen. We confirm it by a rule of three

2 moles of sulfide can react to 3 moles of O₂

Therefore 3 moles of ZnS will react to (3 . 3) / 2 = 4.5 moles (we need 4.5 moles of O₂ and we only have 2 moles, that's why the O₂ is the limiting)

Excess reagent is the zinc (II) sulfide

3 moles of oxygen react to 2 moles of ZnS

2 moles of O₂ will react to (2 . 2) / 3 = 1.33 moles of ZnS (it is ok, be cause we have 3 moles, and we need only 1.33)

After the reaction is complete ( 3 - 1.33) = 1.67 moles of sulfide remain.

6 0
3 years ago
Read 2 more answers
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