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lbvjy [14]
3 years ago
7

(1) Some years ago, a crucial experimental error was made during the work-up of the reaction. Instead of adding the reaction mix

ture to the cold acid solution, the inverse addition was carried out. What do you think happened when the acid solution was added to the reaction mixture
Chemistry
1 answer:
bonufazy [111]3 years ago
5 0

Answer:

Salts will be formed and the pH of the new mixture will fall.

Explanation:

What should be: The reaction mixture should be added to the cold acid solution.

The error: Cold acid solution was added to the reaction mixture.

What happens with this?

The neutralization of a solution creates salts. The combination of positive and negative ions in the reaction also forms water. Assuming the pH of the reaction mixture was neutral before the addition of the acid, after the addition of the acid solution the pH will drop. Recall that a neutral solution has a pH of 7. So the pH of this new solution will drop to less than 7 because of the addition of an acid.

If the required procedure for the chemical process was followed, the reaction mixture added to the cold acid would have resulted in a stronger base solution. In other words, the pH of the new solution would be higher.

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Determination of the amount of patassium hydroxide in patassium hydroxide/Sodium carbonate mixture
Eva8 [605]

Answer:

do you still need this answer?

Explanation:

6 0
4 years ago
Jupiter’s moon Io was discovered to have high concentrations of sulfur oxides in its atmosphere. This, in combination with resea
deff fn [24]

Answer:

S₂O₂  

Explanation:

The multiplying prefix di- means "two."

Thus, a molecule of disulfur dioxide has two atoms of sulfur and two atoms of oxygen.

The formula is S₂O₂.

4 0
3 years ago
4Na + O2 2Na2O
beks73 [17]
4
N
a
+
O
2
→
2
N
a
2
O
.
By the stoichiometry of this reaction if 5 mol natrium react, then 2.5 mol
N
a
2
O
should result.
Explanation:
The molecular mass of natrium oxide is
61.98

g
⋅
m
o
l
−
1
. If
5

m
o
l
natrium react, then
5
2

m
o
l
×
61.98

g
⋅
m
o
l
−
1

=

154.95

g
natrium oxide should result.
So what have I done here? First, I had a balanced chemical equation (this is the important step; is it balanced?). Then I used the stoichiometry to get the molar quantity of product, and converted this molar quantity to mass. If this is not clear, I am willing to have another go
5 0
3 years ago
For the following reaction, 22.6 grams of nitrogen monoxide are allowed to react with 4.64 grams of hydrogen gas . nitrogen mono
antiseptic1488 [7]

Answer:

- 10.5 g of N₂

- Limiting reagent: NO

- 3.13 g of H₂ remains

Explanation:

First of all we state the reaction: 2NO(g) + 2H₂(g) → 2H₂O(l) + N₂(g)

We need to find out the limiting reactant and the excess reagent

Ratio in the reactants is 2:2. Let's convert the mass to moles:

22.6 g / 30 g/mol = 0.753 moles of NO

4.64 g / 2 g/mol = 2.32 moles of H₂

Certainly the limiting reagent is the NO and the excess reactant is the hydrogen:

- For 0.753 moles of NO, we need 0.753 moles of H₂ (we have 2.32 moles)

- For 2.32 moles of H₂, we need 2.32 moles of NO (and we don't have enough NO, because we only have 0.753 moles)

As the H₂ is the excess reagent, some moles still remains after the reaction is complete → 2.32 mol - 0.753 mol = 1.567 moles

We convert the moles to mass: 1.567 mol . 2g /1mol = 3.13 g of H₂ remains

As the NO is the limiting reagent, we can work with the equation:

We propose this rule of three: 2 moles of NO can produce 1 mol of N₂

Then, 0.753 moles of NO must produce (0.753 . 1) /2 = 0.376 moles of N₂

We convert the moles to mass 0.376 mol . 28 g / 1 mol = 10.5 g

3 0
3 years ago
Which statement describes the ocean floor?
Keith_Richards [23]

Answer: C

Explanation: The ocean floor is largely unexplored so no one knows what it is like.

4 0
2 years ago
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