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Rzqust [24]
3 years ago
9

Are these synthesis decomposition single replacement or double replacement?

Chemistry
1 answer:
marishachu [46]3 years ago
7 0

Answer:

1. Synthesis

2. Decomposition

3. Single replacement

4. Synthesis

5. Decomposition

6. Synthesis

Explanation:

Kind of a hard picture to look at but let me define each chemical reaction:

Synthesis:

a + b ---> ab   In synthesis elements/compounds come together to form new                compounds

Decomposition:

ab ---> a + b   In decomposition a compound breaks down to form 2 elements/compounds

Single replacement:

a + bc ---> b + ac   In a single replacement one element/compound takes the place of another element/compound.

Double replacement

ab + cd ---> ad + bc In a double replacement 2 compounds exchange different elements/compounds.

Now, let's go through the assignment

1. P + O2 --> P4O10  This is a synthesis reaction because the two elements (P and O) came together to form one compound.

2. HgO ---> Hg + O2  This is a decomposition reaction because HgO broke into separate elements Hg and O.

3. Cl2 + NaBr ---> NaCl + Br2  This is a single replacement reaction because chlorine (Cl) replaced the spot of bromine (Br) to bond with sodium (Na).

4.  Mg + O2 ---> MgO  This is a synthesis reaction because two elements (Mg and O) came together to form one compound.

5. Al2O3 ---> Al + O2  This is a decomposition reactions because Al2O3 broke into separate elements Al and O.

6. H2 + N2 ---> NH3  This is a synthesis reaction because two elements (H and N) came together to form one compound.

<em>I hope this helps!!</em>

<em>- Kay :)</em>

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Answer:

Explanation:

Ionization energy:

It is the minimum amount of energy required to remove the electron from isolated gaseous atom to make the ion.

As we move from left to right across the periodic table the number of valance electrons in an atom increase. The atomic size tend to decrease in same period of periodic table because the electrons are added with in the same shell.

When the electron are added, at the same time protons are also added in the nucleus. The positive charge is going to increase and this charge is greater in effect than the charge of electrons. This effect lead to the greater nuclear attraction. The electrons are pull towards the nucleus and valance shell get closer to the nucleus. As a result of this greater nuclear attraction atomic radius decreases and ionization energy increases because it is very difficult to remove the electron from atom and more energy is required.  Where as,

When we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.

As the size of atom increases the ionization energy from top to bottom also  decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.

4 0
4 years ago
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4 0
3 years ago
Which of the following combination of elements would result in covalent compound? * W X Y Z Vand X Wand Z Y and Z Wand y​
TEA [102]

Answer:

C. Y & Z

Explanation:

V, W are imaginary metals here because their valence electrons are typically less than 4. X, Y, Z are non-metals and have higher valence electrons. Here, if V or W bind with X, Y, or Z we make ionic bond (because metal + non metal = ionic). But, if X binds with Y or Z or any combinations of any two of the three non-metals results in covalent bond (non metal + non metal = covalent).

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3 years ago
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Paraphin [41]
<h2>Answer:  C) 1s²2s²2p⁶</h2>

<h3>Explanation:</h3>

A noble gas has 8 electrons between the p and s orbitals of the outer shell. Helium is the exception because it only has two electrons.

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7 0
3 years ago
Determine the [OH−] of a solution that is 0.115 M in CO32−. For carbonic acid (H2CO3), Ka1=4.3×10−7 and Ka2=5.6×10−11.
lianna [129]

Answer:

[OH⁻] = 4.3 x 10⁻¹¹M in OH⁻ ions.

Explanation:

Assuming the source of the carbonate ion is from a Group IA carbonate salt (e.g.; Na₂CO₃), then 0.115M Na₂CO₃(aq) => 2(0.115)M Na⁺(aq) + 0.115M CO₃²⁻(aq). The 0.115M CO₃²⁻ then reacts with water to give 0.115M carbonic acid; H₂CO₃(aq) in equilibrium with H⁺(aq) and HCO₃⁻(aq) as the 1st ionization step.

Analysis:

            H₂CO₃(aq)     ⇄     H⁺(aq)    +    HCO₃⁻(aq); Ka(1) = 4.3 x 10⁻⁷

C(i)          0.115M                      0                  0

ΔC              -x                        +x                  +x

C(eq)    0.115M - x                   x                    x

            ≅ 0.115M

Ka(1) = [H⁺(aq)][HCO₃⁻(aq)]/[H₂CO₃(aq)] = [(x)(x)/(0.115)]M = [x²/0.115]M

= 4.3 x 10⁻⁷  => x = [H⁺(aq)]₁ = SqrRt(4.3 x 10⁻⁷ · 0.115)M = 2.32 x 10⁻⁴M in H⁺ ions.

In general, it is assumed that all of the hydronium ion comes from the 1st ionization step as adding 10⁻¹¹ to 10⁻⁷ would be an insignificant change in H⁺ ion concentration. Therefore, using 2.32 x 10⁻⁴M in H⁺ ion  concentration, the hydroxide ion concentration is then calculated from

[H⁺][OH⁻] = Kw => [OH⁻] = (1 x 10⁻¹⁴/2.32 x 10⁻⁴)M = 4.3 x 10⁻¹¹M in OH⁻ ions.

________________________________________________________

NOTE: The 2.32 x 10⁻⁴M  value for [H⁺] is reasonable for carbonic acid solution with pH ≅ 3.5 - 4.0.

4 0
3 years ago
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