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3 years ago

Is it easier to open a bottle cap by gripping it with a towel. Why ?

Physics

2 answers:

vesna_86 [32]3 years ago

7 0

Answer:

Yes

Explanaton:

He made you get grip

nata0808 [166]3 years ago

4 0

I would say friction would help you

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The closest star to our solar system is Alpha Centauri, which is 4.12 × 10^16 m away. How long would it take light from Alpha Ce

bonufazy [111]

Time = (distance) / (speed)

Time = (4.12x10^16 m) / (3 x10^8 m/s)

Time = 1.37 x 10^8 seconds

Divide the seconds by 86,400 to get days. Then divide the days by 365 to get years.

Time = about 4.35 years

4 0

3 years ago

what is the density to the nearest hundredths, of a metal with a volume of 3.00 cm3 and a mass of 8.13g?

I am Lyosha [343]

Since D=M/V, the answer would be 2.7

8 0

3 years ago

La) What is meant by the term Basic Quantities.

castortr0y [4]

Answer:

A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.

Explanation:

A basic quantity is basically the physical quantity that can not be defined in terms of other quantities.

Some of the names of the basic quantities include:

Mass, denoted by the symbol 'm', with S.I. unit 'kg'
Length, denoted by symbol 'l', with S.I. unit 'm'
Time, denoted by symbol 't', with S.I. unit 's'
Current, denoted by 'I', with S.I. unit 's' 'A'
Temperature, denoted by 'T', with S.I. unit 'K'
Amount of substance, denoted by 'n', with S.I. unit 'mol'
Luminous Intensity, denoted by 'Iv', with S.I. unit 'cd'

A basic quantity is chosen arbitrarily.

5 0

3 years ago

The greatest height reported for a jump into an airbag is 99.4 m by stuntman Dan Koko. In 1948 he jumped from rest from the top

vaieri [72.5K]

Answer:

v = 44,16 m/s

Explanation:

We will fixate our reference in the starting point from where Dan jumped of, at the top of the Casino. Therefore, the displacement made when dan reached the airbag would be of y= -99,4 m viewed from our reference. We describe the motion of dan with the equation:

$v_y^2 =v_0^2 +2ay$

Dan jumped from the rest, that means that the initial velocity v_0=0, therefore:

$v_y^2 =2ay \rightarrow v_y = \sqrt{2ay}$

Since Dan is moving in the negative axis regarding our reference point, we take the negative root of the equation.

v_y=-√(2*(-9,81 m/s^2 )*(-99,4 m) )=44,1613 m/s $v_y =- \sqrt{2*(-9,81 m/s^2)*(-99,4 m)} = 44,1613 m$

So, if we don’t take the air resistance into account, Dan would have achieved an velocity of 44,16 m/s when he reached the airbag.

I hope everything was clear with my explanation. If you need anything else, let me know. Have a great day :D

7 0

4 years ago

A radar operates at a wavelength of 3 centimeters. what is the frequency of the these waves? the speed of light is 3 × 108 m/s .

aliya0001 [1]

We are given information:
λ $= wavelength = 3cm = 0.03m \\ 
c = speed of light = 3* 10^{8}m/s$

Formula that connects wavelength and frequency is:
$frequency= \frac{speed of light}{wavelength} \\ f= \frac{3* 10^{8}}{0.03} \\ f=1 * 10^{10} Hz = 10GHz$

4 0

3 years ago