Answer:
<em>D.) state of matter</em>
Explanation:
it can undergo chemical but not nuclear.
Answer:
(a) Magnitude of static friction force is 109 N
(b) Minimum possible value of static friction is 0.356
Solution:
As per the question;
Horizontal force exerted by the girl, F = 109 N
Mass of the crate, m = 31.2 kg
Now,
(a) To calculate the magnitude of static friction force:
Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:
F = f = 109 N
(b) The maximum possible force of friction between the floor and the crate is given by:

where
N = Normal reaction = mg
Thus

For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.




Answer:
g=GM/R^2
Universal Gravutation Constant:
f=GM×m/R^2
Force can be also expressed as
f=m×g
so,
mg=GMxm/R^2
The m gets cancelled so
g=GM/R^2
Answer:
It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.
Explanation:

Since the initial velocity of a dropped object is 0, we can make this the equation:


The final velocity can be calculated with the formula:

Once again, since there is no initial velocity:

Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.
Hope this helps!