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djverab [1.8K]
2 years ago
5

The average diameter of one tennis ball in a package of three is 6.8 cm. Which of the following is the combined volume of all th

ree tennis balls? Use 3.14 for pie and round your final answer to the nearest hundredth
Physics
1 answer:
Crank2 years ago
4 0

We want to find the combined volume of 3 tennis balls. We will get that the combined volume is 493.7 cm^3

First, remember that for a sphere of diameter D, the volume is:

V = \frac{4}{3}*3.14*(\frac{D}{2})^3

Where 3.14 is pi.

Here we know that the average diameter of a tennis ball is 6.8cm, then we can replace that in the above equation to find the volume (in average) of a single tennis ball:

V = \frac{4}{3}*3.14*(\frac{6.8cm}{2})^3 = 164.5 cm^3

Now, in 3 balls of tennis, the combined volume will be 3 times the above one, this is:

3*V = 3*164.5cm^3 = 493.7 cm^3

If you want to learn more about volumes, you can read:

brainly.com/question/10171109

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<em>D.) state of matter</em>

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2 years ago
A girl exerts a horizontal force of 109 N on a crate with a mass of 31.2 kg. HINT (a) If the crate doesn't move, what's the magn
vesna_86 [32]

Answer:

(a) Magnitude of static friction force is 109 N

(b) Minimum possible value of static friction is 0.356

Solution:

As per the question;

Horizontal force exerted  by the girl, F = 109 N

Mass of the crate, m = 31.2 kg

Now,

(a) To calculate the magnitude of static friction force:

Since, the crate is at rest, the forces on the crate are balanced and thus the horizontal force is equal to the frictional force, f:

F = f = 109 N

(b) The maximum possible force of friction between the floor and the crate is given by:

f_{m} = \mu_{s}N

where

N = Normal reaction = mg

Thus

f_{m} = \mu_{s}mg

For the crate to remain at rest, The force exerted on the crate must be less than or equal to the maximum force of friction.

f\leq f_{m}

f \leq \mu_{s}mg

109 \leq \mu_{s}\times 31.2\times 9.8

\mu_{s}\geq 0.356

7 0
2 years ago
PROVE THAT G = GM/R² WHERE THE SYMBOLS HAS THEIR USUAL MEANINGS<br>​
butalik [34]

Answer:

g=GM/R^2

Universal Gravutation Constant:

f=GM×m/R^2

Force can be also expressed as

f=m×g

so,

mg=GMxm/R^2

The m gets cancelled so

g=GM/R^2

8 0
3 years ago
If a box of supplies is dropped from the cargo hold of an airplane travelling at an altitude of 4,410 meters how long will it ta
Paraphin [41]

Answer:

It will take 30 seconds to reach the ground, and it will be travelling at 294 m/s when it does so. This means that its average velocity was 147 m/s.

Explanation:

d=v_ot+\dfrac{1}{2}at^2

Since the initial velocity of a dropped object is 0, we can make this the equation:

d=\dfrac{1}{2}at^2 \\\\4410=\dfac{1}{2}(9.8)t^2 \\\\t^2=900

t=30\text{ seconds}

The final velocity can be calculated with the formula:

v_f=v_o+at

Once again, since there is no initial velocity:

v_f=at \\\\v_f=(9.8)(30)=294m/s

Since the initial velocity is 0, the average vertical velocity is 294/2=147 m/s.

Hope this helps!

5 0
3 years ago
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