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madreJ [45]
3 years ago
15

(a) the gamma rays produced by a radioactive nuclide used in medical imaging (b) radiation from an FM radio station at 93.1 MHz

on the dial (c) a radio signal from an AM radio station at 680 kHz on the dial (d) the yellow light from sodium vapor streetlights (e) the red light of a light-emitting diode, such as in a calculator display Rank labels from high wavelength to low.
Physics
1 answer:
lawyer [7]3 years ago
7 0

Answer:

They can be rank in the following way:

  • A radio signal from an AM radio station at 680 kHz on the dial
  • Radiation from an FM radio station at 93.1 MHz on the dial
  • The red light of a light-emitting diode, such as in a calculator
  • The yellow light from sodium vapor streetlights
  • The gamma rays produced by a radioactive nuclide used in medical

Explanation:

The electromagnetic spectrum is the distribution of radiation due to the different frequencies at which it radiates and its different intensities, that radiation is formed by electromagnetic waves, which are transverse waves formed by an electric field and a magnetic field perpendicular to it.

Radiation is distributed along that electromagnetic spectrum according to the wavelength or frequency.

Highest frequencies

X-rays

Ultraviolet rays

Visible region

Lower frequencies

Infrared

Microwave

Radio waves

Radio waves and the visible region (yellow light, red light) are part of the electromagnetic spectrum, any radiation of that electromagnetic spectrum has a speed of 3.00x10^{8}m/s in vacuum.

However, the following equation relates the velocity, the frequency, and the wavelength:

c = \nu \cdot \lambda  (1)

\nu = \frac{c}{\lambda} (2)

It can be see in equation 2 that the frequency and the wavelength are inversely proportional (when the frequency increases the wavelength decreases).

Therefore, for what was already discussed, they can be rank in the next way:

  • A radio signal from an AM radio station at 680 kHz on the dial
  • Radiation from an FM radio station at 93.1 MHz on the dial
  • The red light of a light-emitting diode, such as in a calculator
  • The yellow light from sodium vapor streetlights
  • The gamma rays produced by a radioactive nuclide used in medical

Summary:

In the case of the radio waves can be used:

Case for \nu = 93.1 MHz:

\lambda = \frac{c}{\nu}

\lambda = \frac{3x10^{8}m/s}{93100000s^{-1}}

\lambda = 3.22m

Case for \nu = 680 kHz:

\lambda = \frac{c}{\nu}

\lambda = \frac{3x10^{8}m/s}{680000s^{-1}}

\lambda = 441.17m

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8 0
4 years ago
an open cart is moving along a straight frictionless horizontal track. When rain starts falling vertically into the cart, what h
fgiga [73]

Answer:

The speed of the cart decreases

Explanation:

The track is frictionless, so we can consider the cart as isolated system (no external forces acting on it): therefore, the momentum of the cart is conserved

p=mv=const.

where m is the mass and v the speed of the cart.

When it starts raining, some water falls into the cart: this means that the mass of the cart, m, increases. But we said that the momentum, p, must remain constant: in order for that to happen, this means that the speed of the cart, v, must decrease (because the relationship mv=const. is an inverse relationship, so if m increases, v must decrease).

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The horizontal component of an angular distance can be calculated by multiplying the distance with the cosine of the angle, Dx = D * cos θ

While the vertical component is calculated by multiplying the distance with the sine of the angle, Dy = D * sin θ

The resultant displacement can then be obtained using the formula for hypotenuse and summations of each component:

R^2 = (summation of Dx)^2 + (summation of Dy)^2

summation of Dx = 600 * cos47 + 500 * cos128 + 300 * cos209 + 400 * cos(-77) = -71.0372

summation of Dy = 600 * sin47 + 500 * sin128 + 300 * sin209 + 400 * sin(-77) = 297.6267

<span>                        Note: you have to draw the lines to correctly determine the angles</span>

R^2 = (-71.0372)^2 + 297.6267^2

R = 306 m

The resultant angle is:

tan θ = Dy / Dx

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θ = 103˚ = [N 13˚ W]

Therefore displacement is 306 m <span>[N 13˚ W].</span>

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to find the equivalent energy in calories:

x=\frac{(1 cal)(2.56\cdot 10^4 J)}{4186 J}=6.1 cal

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