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Explanation:
Formula to determine the critical crack is as follows.
= 1,
= 24.1
[/tex]\sigma_{y}[/tex] = 570
and,
= 427.5
Hence, we will calculate the critical crack length as follows.
a =
=
=
Therefore, largest size is as follows.
Largest size = 2a
=
=
Thus, we can conclude that the critical crack length for a through crack contained within the given plate is .
Ranking of de Broglie wavelengths from largest to smallest is electron > proton > helium
- De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
- From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship
De Broglie's relationship is given by .....(1) , where λ is known as de Broglie wavelength and m is mass , v is velocity , h = Plank’s constant.
From equation (1) wavelength and mass has an inverse relation .
Mass of helium is 4 times the mass of the proton and proton has a greater mass than electron.
According to equation (1) , less the mass higher will be the wavelength
Hence electron having less mass have higher wavelength and then proton and then helium having large mass will have less wavelength .
Thus, order should be electron > proton > helium .
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