The relationship between electrical potential energy
(PE), capacitance (C), and potential difference (V) can be expressed through
the equation,
<span> V = PE / C</span>
V is equal to the quotient of potential energy and
capacitance.
When we substitute the known values from the item,
<span> V = 73 J/ 120 C</span>
<span> V = 0.61 J/C</span>
<span>Thus, the voltage or potential difference is equal to
0.61 V. </span>
14.136 J as shown on the photo with two thought processes but overall same calculation
Answer:
x = 541 m
Dt = ?
vi = 12 m/s
vf = 0 (stop)
a = ?
Use vf^2 = vi^2 + 2a(Dx): 0^2 = (12 m/s)^2 + 2a(541 m), a = -144 m^2/s^2, a = -144 m^2/s^2/(1082 m) = -.1331 m/s/s or -.13 m/s/s
Answer:30
Explanation:
Current=60 milliamps
Current=(voltage)/(resistance)
60=(voltage)/(resistance)
Doubling the resistance means multiplying both sides by 1/2
60x1/2=(voltage)/(resistance) x 1/2
30=(voltage)/2(resistance)
Therefore the resistance would be 30 milliamp if we double the resistance