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Hatshy [7]
3 years ago
6

Do you think sugar would be soluble in hexane based on its structure

Chemistry
1 answer:
Fittoniya [83]3 years ago
5 0

Answer:

The dipole forces (particularly H-bonds) that keep polar solute molecules together can be replaced by polar solute-solvent interactions, so substances that are predominantly polar (like glucose) dissolve in polar solvents like water but not in nonpolar solvents like hexane (H-bonds).

Explanation:

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2. force → the rate at which an object changes position; distance divided by time
yaroslaw [1]

Answer:

2. True

3. True

4. False

Explanation:

4 0
3 years ago
A cold pack is snapped, and the chemical reaction causes the pack to feel cold. Which kind of reaction is this
pogonyaev
Endothermic, as it makes its surroundings cooler.
3 0
3 years ago
"the order-of-magnitude of the diameter of an" atom is closest to
marissa [1.9K]
The standard size of an atom is <span>1 X 10 -8 cm.
hope I helped :)</span>
5 0
4 years ago
How do you determine the correct subscripts in a chemical formula
VMariaS [17]

BY CHECKING THE REACTIVITY OF AN ELEMENT WHICH IS MOST REACTIVE OR NOT AND YOU STUDY TYPE OF CHEMICAL REACTION IN 1 CH AND YOU CHECK THE REACTIVITY OF ELEMENTS IN 3 CH METALS AND NON METALS PAGE NO 45 IN NCERT BOOK

4 0
4 years ago
The change in entropy of 20.0 moles of ideal monatomic constant volume gas as it changes from an initial temperature 300 K to it
Gre4nikov [31]

Answer:

668.9K is the final temperature

Explanation:

The change in entropy, ΔS, of an ideal monoatomic gas is obtained using the equation:

ΔS = n*Cv*ln (T2/T1)

<em>Where ΔS is change in entropy = 200J/K</em>

<em>n are moles = 20.0mol</em>

Cv is 3/2R for an ideal monoatomic gas (3/2*8.314J/molK)

T2 is final Temperature and T1 initial temperature = 300K

Replacing:

ΔS = n*Cv*ln (T2/T1)

200J/K = 20.0mol*3/2 *8.314J/molK*ln (T2/300K)

0.80186 = ln (T2/300K)

2.23 = T2 / 300K

<h3>668.9K is the final temperature</h3>
7 0
3 years ago
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