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ollegr [7]
3 years ago
8

The same pipe is used to carry both air and water. For the same fluid velocity and friction factor for the air and water flows:

the pressure drop for the air flow is greater than that for the water flow. the pressure drop for the air flow equals the pressure drop for the water flow. the pressure drop for the water flow is greater than that for the air flow.

Physics
1 answer:
VladimirAG [237]3 years ago
4 0

Answer:

the pressure drop for the water flow is greater than that for the air flow.

Explanation:

Detailed analysis of the problem is show below.

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What happens to the resistance of a wire as its length increases? A. The resistance decreases. B. The resistance is not affected
kondor19780726 [428]

Answer:

D. The resistance increases.

Explanation:

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3 years ago
A roller coaster has a mass of 650 kg. It sits at the top of a hill with height 78 m. If it drops from this hill, how fast is it
Leto [7]

Answer:

The roller coaster is going at 39.1 m/s when it reaches the bottom

Explanation:

We use conservation of mechanical energy to solve this problem. So, we need to estimate the potential energy of the cart at the top of the hill while it is sitting steady there. Such will give us the cart initial Total Energy (TE) since its kinetic energy at that moment is zero (the cart is not moving, just sitting at the top of the hill).

Its initial potential energy (Ui) is therefore: Ui=m*g*h=650 * 9.8 * 78=496860 J

Notice also that all units given are in the SI system, (including the acceleration of gravity g) and therefore the answer is in Joules.

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When we look at what happens the instant the cart reaches the bottom, at that point it has all kinetic energy and zero potential energy (h is zero at the bottom of the hill). Final Kinetic Energy is by definition: Kf =\frac{1}{2} m*v^2=\frac{1}{2}650*v^2=325 v^2

Therefore, the conservation of mechanical energy tells us that:

ET_i=ET_F\\U_i+K_i=U_F+K_F\\496860 J +0J=0J+325v^2

We can solve for the final velocity of the roller coaster in this equation by solving for it in the equation:

496860 J +0J=0J+325v^2\\\\496860J=325v^2\\v^2=\frac{496860}{325} =1528.8\\v=\sqrt{1528.8} = 39.1 \frac{m}{s}

The velocity should result with units of meters/second since all quantities were given in SI units.

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3 years ago
If gravitational pull got three times stronger what happens to your weight?
saveliy_v [14]
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8 0
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katovenus [111]
Weight, hight, and temperature are all typws of measurements.
6 0
4 years ago
The study of alternating electric current requires the solutions of equations of the form i equals Upper I Subscript max Baselin
KiRa [710]

Answer:

Explanation:

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