2 years ago

What if 36 is 45 percent, what is the other 55 percent

Mathematics

1 answer:

coldgirl [10]2 years ago

5 0

Answer:

Step-by-step explanation:

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3 years ago

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Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles. She can ride 9 mph faster than she can walk. How f

Marrrta [24]

Answer:

$\frac{48}{r+9}=\frac{12}{r}$

Step-by-step explanation:

Let r represent Linda's walking rate.

We have been given that Linda can ride 9 mph faster than she can walk, so Linda's bike riding rate would be $t+9$ miles per hour.

$\text{Time}=\frac{\text{Distance}}{\text{Rate}}$

We have been given that Linda can bicycle 48 miles in the same time as it takes her to walk 12 miles.

$\text{Time while riding}=\frac{48}{r+9}$

$\text{Time taken while walking}=\frac{12}{r}$

Since both times are equal, so we will get:

$\frac{48}{r+9}=\frac{12}{r}$

Therefore, the equation $\frac{48}{r+9}=\frac{12}{r}$ can be used to solve the rates for given problem.

Cross multiply:

$48r=12r+108$

$48r-12r=12r-12r+108$

$36r=108$

$\frac{36r}{36}=\frac{108}{36}$

$r=3$

Therefore, Linda's walking at a rate of 3 miles per hour.

Linda's bike riding rate would be $t+9\Rightarrow 3+9=12$ miles per hour.

Therefore, Linda's riding the bike at a rate of 12 miles per hour.

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