1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
madreJ [45]
3 years ago
8

During a heating or cooling process, how are changes in enthalpy and temperature related?​

Chemistry
1 answer:
Deffense [45]3 years ago
5 0

Answer:

answer this and ill answer that

Explanation:

during a heating or cooling process, how are changes in enthalpy and temperature related?​

You might be interested in
Steps of scientific inquiry?
vlabodo [156]
1. Figure out a problem
2. Research
3. Hypothesis  
4. Experiment
5. Analyze results 
6. Conclusion 
7. Communicate your results

Hope This Helps. :D <span />
8 0
3 years ago
Read 2 more answers
A beaker with 155 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and conjug
OverLord2011 [107]

Answer:

ΔpH = 0.296

Explanation:

The equilibrium of acetic acid (CH₃COOH) in water is:

CH₃COOH ⇄ CH₃COO⁻ + H⁺

Henderson-Hasselbalch formula to find pH in a buffer is:

pH = pKa + log₁₀ [CH₃COO⁻] / [CH₃COOH]

Replacing with known values:

5.000 = 4.740 + log₁₀ [CH₃COO⁻] / [CH₃COOH]

0.260 =  log₁₀ [CH₃COO⁻] / [CH₃COOH]

1.820 = [CH₃COO⁻] / [CH₃COOH] <em>(1)</em>

As total molarity of buffer is 0.100M:

[CH₃COO⁻] + [CH₃COOH] = 0.100M <em>(2)</em>

Replacing (2) in (1):

1.820 = 0.100M - [CH₃COOH] / [CH₃COOH]

1.820[CH₃COOH] = 0.100M - [CH₃COOH]

2.820[CH₃COOH] = 0.100M

[CH₃COOH] = 0.100M / 2.820

[CH₃COOH] = <em>0.035M</em>

Thus: [CH₃COO⁻] = 0.100M - 0.035M = <em>0.065M</em>

5.40 mL of a 0.490 M HCl are:

0.0054L × (0.490mol / L) = 2.646x10⁻³ moles HCl.

Moles of CH₃COO⁻ are: 0.155L × (0.065mol / L) = 0.0101 moles

HCl reacts with CH₃COO⁻ thus:

HCl + CH₃COO⁻ → CH₃COOH

After reaction, moles of CH₃COO⁻ are:

0.0101 moles - 2.646x10⁻³ moles = <em>7.429x10⁻³ moles of CH₃COO⁻</em>

<em />

Moles of CH₃COOH  before reaction are: 0.155L × (0.035mol / L) = 5.425x10⁻³ moles of CH₃COOH. As reaction produce 2.646x10⁻³ moles of CH₃COOH, final moles are:

5.425x10⁻³ moles +  2.646x10⁻³ moles = <em>8.071x10⁻³ moles of CH₃COOH</em>. Replacing these values in Henderson-Hasselbalch formula:

pH = 4.740 + log₁₀ [7.429x10⁻³ moles] / [8.071x10⁻³ moles]

pH = 4.704

As initial pH was 5.000, change in pH is:

ΔpH = 5.000 - 4.740 = <em>0.296</em>

4 0
3 years ago
What is the concentration of a solution made by diluting 25ml of 6.0M HCI to a final volume of 750
Varvara68 [4.7K]

Answer:

Explanation:

The

7 0
3 years ago
Convert 512 kilograms to milligrams.<br><br> 0.000512<br> 0.512<br> 512,000<br> 512,000,000
olga55 [171]
The answer is D! 512000000
5 0
3 years ago
Read 2 more answers
Calculate the H3O+ concentration and then pH in a 0.100 M HC2H3O2 solution that is
Lana71 [14]

Answer:

Please check with the attachment posted.

Please do confirm the answer.

5 0
3 years ago
Other questions:
  • Consider the SCl2 molecule. (a) What is the electron config- uration of an isolated S atom? (b) What is the electron con- figura
    11·1 answer
  • The standard cell potential (e°cell) of the reaction below is -0.55 v. the value of δ g° for the reaction is ________ j/mol. i2
    10·1 answer
  • Temperature is used to measure the movement of particles such as atoms and molecules. As temperature increases, what is true of
    7·2 answers
  • Which properties are characteristic of metalloids?
    8·2 answers
  • What will happen if TWO light bulbs are placed at point D, and point B is closed?
    5·1 answer
  • Which atom in the O-F bond has a partial positive charge (δ⁺)?
    5·1 answer
  • Which of the following best describes where cellular respiration occurs?
    8·2 answers
  • What is another name for the nucleotides in DNA?
    9·1 answer
  • Who is the intended audience?​
    6·2 answers
  • Which of the following is/are considered alcohols?
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!