Answer:
992.302 K
Explanation:
V(rms) = 750 m/s
V(rms) = √(3RT / M)
V = velocity of the gas
R = ideal gas constant = 8.314 J/mol.K
T = temperature of the gas
M = molar mass of the gas
Molar mass of CO₂ = [12 + (16*2)] = 12+32 = 44g/mol
Molar mass = 0.044kg/mol
From
½ M*V² = 3 / 2 RT
MV² = 3RT
K = constant
V² = 3RT / M
V = √(3RT / M)
So, from V = √(3RT / M)
V² = 3RT / M
V² * M = 3RT
T = (V² * M) / 3R
T = (750² * 0.044) / 3 * 8.314
T = 24750000 / 24.942
T = 992.302K
The temperature of the gas is 992.302K
Note : molar mass of the gas was converted from g/mol to kg/mol so the value can change depending on whichever one you use.
I think it is D
Hope this help you?
When the pressure is doubled the volume will be half as the pressure increase due to the frequent collision of molecules so with the decrease in volume the pressure will increase as Boyles law
Answer:
Explanation:
For the reaction: 2X + 3Y = 3Z, the combination of 2.00 moles of X with 2.00
moles of Y produces 1.75 moles of Z
2 mol 2 mol 1.75 mol
2X + 3Y = 3Z
need 2 mol 3 mol to give 3 mol
3 mol Z/3 mol Y= 1 to 1
should get 2 mol Z
1.75/2 =87.5 % yield
