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777dan777 [17]
1 year ago
5

A gas tank contains 3 gases (N2, O2, and CO2). The total pressure of the gases is 825mmHg. If Pco2 = 125mmHg and Po2= 350mmHg, w

hat is the partial pressure of N2 gas?
Chemistry
1 answer:
DedPeter [7]1 year ago
3 0

Answer:

350mmHg

Explanation:

Use Dalton law

Total=P gas 1+p gas 2+ P gas 3

825=P1+350+125

825=P1+475

825-475= P1

P1= 350 mm Hg

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What eventually happens to gas if its pressureis increased?​
balu736 [363]

Answer:

the rate increases

Explanation:

they are closer to each other, they will collide with each other more frequently and more successful collision

4 0
2 years ago
14. An enzyme-catalyzed reaction was carried out with the substrate concentration initially a thousand times greater than the Km
emmainna [20.7K]

Answer:

27 min

Explanation:

The kinetics of an enzyme-catalyzed reaction can be determined by the equation of Michaelis-Menten:

v = \frac{vmax[S]}{Km + [S]}

Where v is the velocity in the equilibrium, vmax is the maximum velocity of the reaction (which is directed proportionally of the amount of the enzyme), Km is the equilibrium constant and [S] is the concentration of the substrate.

So, initially, the velocity of the formation of the substrate is 12μmol/9min = 1.33 μmol/min

If Km is a thousand times smaller then [S], then

v = vmax[S]/[S]

v = vmax

vmax = 1.33 μmol/min

For the new experiment, with one-third of the enzyme, the maximum velocity must be one third too, so:

vmax = 1.33/3 = 0.443 μmol/min

Km will still be much smaller then [S], so

v = vmax

v = 0.443 μmol/min

For 12 μmol formed:

0.443 = 12/t

t = 12/0.443

t = 27 min

7 0
3 years ago
What is the value of the equilibrium constant at 25 oC for the reaction between the pair: Br2(l) and I-(aq) Use the reduction po
Vikki [24]

Answer:

1.58×10E18

Explanation:

Since we have the reduction potentials we could make decisions regarding which one will be the anode or cathode. Evidently, bromine having the more positive reduction potential will be the cathode while the iodine will be the anode.

E°cell= 1.07- 0.53= 0.54 V

E°cell= 0.0592/n logK

0.54 = 0.0592/2 logK

logK= 0.54/0.0296

logK= 18.2

K= Antilog (18.2)

K= 1.58×10^18

3 0
3 years ago
Please Help 8-9!!!!!!!
seropon [69]

The labeled diagram is given in the image attached.

As it can be seen from the image that freezing is when energy is removed from the system at 0 ⁰ while melting is when energy is added at 0⁰.

Also when energy is added at 100⁰C, it causes boiling while when it is removed at 100⁰C, it causes condensation.


Melting point of water is 0⁰C while boiling point is 100⁰C

3 0
2 years ago
write the chemical formula for the following compound -magnesium chloride, zinc sulphide Sodium,sodium sulphate, calcium bicarbo
Sindrei [870]

Answer:

magnesium chloride: MgCl2

zinc sulphide: ZnS

sodium sulphate: Na2SO4

calcium bicarbonate: Ca(HCO3)2

6 0
3 years ago
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