The answer is 34.1 mL.
Solution:
Assuming ideal behavior of gases, we can use the universal gas law equation
P1V1/T1 = P2V2/T2
The terms with subscripts of one represent the given initial values while for terms with subscripts of two represent the standard states which is the final condition.
At STP, P2 is 760.0torr and T2 is 0°C or 273.15K. Substituting the values to the ideal gas expression, we can now calculate for the volume V2 of the gas at STP:
(800.0torr * 34.2mL) / 288.15K = (760.0torr * V2) / 273.15K
V2 = (800.0torr * 34.2mL * 273.15K) / (288.15K * 760.0torr)
V2 = 34.1 mL
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Answer:
Fault-block mountain
Explanation:
I got it right on the assignment
Thus, there are 1.47 × 10^(23) molecules present in 122 grams of NO2.
Answer:
The mass of titanium displaces 68.6 mL of water is 309.4 g.
Explanation:
Given that:-
Also, 1
= 1 mL
So,
The expression for the calculation of density is shown below as:-
Using the above expression to calculate the mass as:-
Applying the values to calculate the mass as:-
<u>The mass of titanium displaces 68.6 mL of water is 309.4 g.</u>