Answer:
Part A: Q = 0.075C
Part B: E = 187.5J
Part C: I = 50A
Part D: ΔQ 1.53C
Explanation:
Part A
Q = C×V
Given
C = 15μF = 15×10‐⁶ F, V = 5kV = 5000V
Q = 15×10‐⁶× 5000 = 0.075C
Part B
Energy = E = 1/2 ×CV² = 1/2 × 15×10‐⁶ × 5000² = 187.5J
Part C
Given R = 100Ω
V = IR, I = V/R = 5000/100 = 50A
Part D
I = ΔQ/Δt
Given Δt= 90ms = 90×10-³s, I = 17A
ΔQ = I × Δt = 17×90×10-³ = 1.53 C
Explanation:
The given data is as follows.
Fluid is water so, density 
Weight flow rate = 500 lbf/s = 2224.11 N/sec
Cross-sectional area (A) = 
= 0.05184 
Hence, weight flow rate will be given as follows.
w = 
2224.11 N/sec = 
V =
m/s
= 4.373 m/s
Thus, we can conclude that average velocity in the given case is 4.373 m/s.
Answer:
True
Explanation:
When no net force is applied to a moving object, it still comes to rest because of its inertia.
D. When a substance reacts with another substance, it shows its chemical property