Answer:
the MTTF of the transceiver is 50.17
Explanation:
Given the data in the question;
failure modes = 0.1 failure per hour
system reliability = 0.85
mission time = 5 hours
Now, we know that the reliability equation for this situation is;
R(t) = [ 1 - ( 1 - 
)³] 
so we substitute
R(5) = [ 1 - ( 1 - 
)³] 
= 0.85
[ 1 - ( 1 - 
)³] = 0.85
[ 1 - ( 0.393469 )³] = 0.85
[ 1 - 0.06091 ] = 0.85
0.9391 = 0.85
= 0.85 / 0.9391
= 0.90512
MTTF = 5 / -ln( 0.90512 )
MTTF = 50.17
Therefore, the MTTF of the transceiver is 50.17
Answer:
<em>Cout = 11mg/L</em>
Explanation:
Assume Steady State and CSTR, this means Qin = Qout
Given: Qin = 4 000m3/day
Cin = 25mg/L
V = 20 000m3
k = 0.25/day
Find: Cout = ?
outStarting from the mass balance equation for steady state 0 = QCin - QCout - kCoutV
manipulate the equation to get:
\(Cout=Cin(Q/Q+kV)\)
<em>Then simple plug in your givens:
</em>
<em>Cout = (25mg/L)((4000m3/day)/(4000m3/day + 0.25/day(20000m3))
</em>
<em>Cout = 11mg/L</em>
Using
q = k*v,
where q = traffic flow rate, k = density, v = space mean speed.
so, 1800 = k x 40
so, k = 1800/40 = 45 veh/mie on two lanes,
so k = 45/2 = 22.5veh/h/in
