Answer:
The total contraction of the bar is 1.228 mm
Explanation:
The parameters given are;
Length of aluminium bar = 600 mm
Diameter of aluminium bar = 40 mm
Diameter of hole in aluminium bar = 30 mm
Length of hole = 100 mm
Modulus of elasticity of aluminium = 85 GN/m²
Applied compressive load = 180 kN

Where:
δ = Total contraction of the bar
A₁ for the hole section = 
A₂ for the solid section = 
L₁ = 100 mm
L₂ = 600 - 100 = 500 mm

The total contraction of the bar = 1.228 mm.
Answer:
Heat generation per unit volume is 45 KW.
Explanation:
Given that
Thickness of wall = 6 cm
Temperature distribution
-----1
K= 15 W/m.k
As we know that at steady state condition
-----2
Where q is the heat generation per unit volume.
So from equation 1


Now from equation 2
So q= 45 KW
So heat generation per unit volume is 45 KW.
Answer:
Q = 2450 KJ/day
Explanation:
We are given;
The amount of moisture produced by a person while taking shower; m = 0.25 kg/person
Total number of persons in the family; N = 4
Latent heat of vaporization of water:
h_fg = 2450 KJ/kg
Since amount of moisture per person is 0.25kg per day,thus for 4 people, total mass; m_total = 4 x 0.25 = 1 kg per day
The formula for the amount of latent heat added to the space due to shower per day, is given as;
Q = m_total x h_fg
Plugging in the relevant values;
Q = 1 x 2450 = 2450 KJ/day
Answer:
The distance from the entrance at which the boundary layers meet is 0.516m
The distance from the entrance at which the thermal boundary layers meet is 1.89m
Explanation:
For explanation, look at the attached file