Answer: The concentration of
is 0.234 M
Explanation:
According to the neutralization law,
where,
= basicity
= 2
= molarity of
solution = ?
= volume of
solution = 50.0 ml
= acidity of
= 1
= molarity of
solution = 0.375 M
= volume of
solution = 62.5 ml
Putting in the values we get:
Therefore concentration of
is 0.234 M
Answer:
46.3g H2O
Explanation:
start by balancing it: CaC2(s) + 2H2O(g) -> Ca(OH)2(s) + C2H2(g)
then use factor label method to solve
82.4g CaC2 x (1 mol CaC2/64.10g CaC2) x (2 mol H2O/1 mol CaC2) x (18.016g H2O/1 mol H20) = 46.3g H2O