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2 years ago

To fulfill the octet rule electron sharing leads to ____ electrons around each atom?

2 answers:

5 0

D. 8

You can predict it from it's name "Octet" means Eight. Atom must have that number of electron to have a stable structure!

Hope this helps!

Elanso [62]2 years ago

4 0

I believe the correct answer from the choices listed above is option D. To fulfill the octet rule electron sharing leads to 8 <span>electrons around each atom. From the word octet, you can directly say that the number 8 is involved here. Hope this answers the question.</span>

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Elodia [21]

Answer:

Boron (B) Atomic Mass: 10.811

Explanation:

The number of protons and electrons are the same, always. You can find the atomic mass by looking at the periodic table for that atom: 10.811

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2 years ago

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Answer:

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2 years ago

Write the chemical formula for the cation present in the aqueous solution of cuso4.

Inessa05 [86]

The ionic compounds on dissolving in aqueous solution dissociate into their respective ions that are cations and anions.

The ions present in the aqueous solution of $CuSO_4$ are $Cu^{2+}$ and $SO_{4}^{2-}$ .

So, the chemical formula of the cation present in the aqueous solution of $CuSO_4$ is $Cu^{2+}$ .

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2 years ago

Show your work with good use of units, rounding, and significant figures. [Hint: it is good practice to show the value of your a

mel-nik [20]

Heat required : 4.8 kJ

<h3>Further explanation </h3>

The heat to change the phase can be formulated :

Q = mLf (melting/freezing)

Q = mLv (vaporization/condensation)

Lf=latent heat of fusion

Lv=latent heat of vaporization

The heat needed to raise the temperature

Q = m . c . Δt

1. heat to raise temperature from -20 °C to 0 °C

$\tt Q=10\times 2.09\times (0-(-20)=418~J$

2. phase change(ice to water)

$\tt Q=10\times 333=3330~J$

3. heat to raise temperature from 0 °C to 25 °C

$\tt Q=10\times 4.18\times (25-0)=1045~J$

$\tt Q~tot=418+3330+1045=4793~J\rightarrow rounding~and~2~sig~figs=4.8~kJ$

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2 years ago

ammonia gas reacts with oxygen gas, o2(g), to produce nitrogen dioxide and water. when 28.5 g of ammonia gas reacts with 83.4 g

jolli1 [7]

The percent yield of the reaction between ammonia gas with oxygen gas is 90.52%.

A chemical reaction between ammonia gas (NH3) with oxygen gas (O2)

NH₃ + O₂ → NO₂ + H₂O

The balanced reaction 4NH₃ + 7O₂ → 4NO₂ + 6H₂O

Calculate the number of moles from the reactant

Ammonia gas
Molar mass N = 14 gr/mol
Molar mass H = 1 gr/mol
Molar mass NH₃ = 14 + (3 × 1) = 14 + 3 = 17 gr/mol
mass = 28.5 grams
n = m ÷ molar mass = 28.5 ÷ 17 = 1.68 mol
Oxygen gas
Molar mass O = 16 gr/mol
Molar mass O₂ = 16 × 2 = 32 gr/mol
mass = 83.4 grams
n = m ÷ molar mass = 83.4 ÷ 32 = 2.61 mol
n O₂ ÷ coefficient O₂ = 2.61 ÷ 7 = 0.37
n NH₃ ÷ coefficient NH₃ = 1.68 ÷ 4 = 0.42
0.42 > 0.37 it means that the ammonia gas is in excess and the O₂ is limiting.

According to stoichiometry, the number of moles NO₂ with the number of moles O₂ has the ratio with the coefficient in reaction.

Theoretically the number moles of NO₂
n O₂ : n NO₂ = 7 : 4
2.61 : n NO₂ = 7 : 4
n NO₂ = 4 x 2.61 : 7 = 1.49 mol
The actual number of moles NO₂
Molar mas NO₂ = 14 + (16 × 2) = 14 + 32 = 46 gr/mol
n NO₂ = m ÷ molar mass = 61.9 ÷ 46 = 1.35 mol

The percent yield NO₂ is the ratio of the actual number of moles NO₂ with the theoretical number of moles NO₂ times 100%.

P = (1.35 ÷ 1.49) × 100%

P = 0.9052 × 100%

P = 90.52%

Learn more about stoichiometry here: brainly.com/question/13691565

#SPJ4

7 0

1 year ago