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Pachacha [2.7K]
2 years ago
11

How many moles of nitrogen, N, are in 62.0 g of nitrous oxide, N2O?​

Chemistry
1 answer:
SSSSS [86.1K]2 years ago
8 0
Answer- the estimated number is 4 moles but it actually is 3.86 moles
Explanation
hi i hope your days been amazing and know that your loved⋆ ˚。⋆୨୧˚ ˚୨୧⋆。˚ ⋆
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Chemistry question! Please explain!
Ilya [14]
There are no numbers provided so I will try to explain the equation. If you want to find the percent error you would do theoretical (the number it’s supposed to be) minus experimental (the number you got in the experiment) over the theoretical value (same as the first one.) You must multiply this by 100 in order to show the actual percentage rather than very low decimals. You want the percent error to be as low as possible because the lower it is the less mistakes happened. Mistakes can include too much/less of solvent, solution, or the glassware wasn’t clean enough, and much much more.

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6 0
4 years ago
What is carboxylic acid?​
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Answer:

Carboxylic acid

A carboxylic acid is an organic acid that contains a carboxyl group attached to an R-group. The general formula of a carboxylic acid is R−COOH or R−CO₂H, with R referring to the alkyl, alkenyl, aryl, or other group. Carboxylic acids occur widely. Important examples include the amino acids and fatty acids.

7 0
3 years ago
Plz help!!! This is timed!!!
pogonyaev
58.7 %

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7 0
2 years ago
Determine the pHpH of an HFHF solution of each of the following concentrations. In which cases can you not make the simplifying
PIT_PIT [208]

The question is incomplete, complete question is :

Determine the pH of an HF solution of each of the following concentrations. In which cases can you not make the simplifying assumption that x is small? (K_a for HF is 6.8\times 10^{-4}.)

[HF] = 0.280 M

Express your answer to two decimal places.

Answer:

The pH of an 0.280 M HF solution is 1.87.

Explanation:3

Initial concentration if HF = c = 0.280 M

Dissociation constant of the HF = K_a=6.8\times 10^{-4}

HF\rightleftharpoons H^++F^-

Initially

c          0            0

At equilibrium :

(c-x)      x             x

The expression of disassociation constant is given as:

K_a=\frac{[H^+][F^-]}{[HF]}

K_a=\frac{x\times x}{(c-x)}

6.8\times 10^{-4}=\frac{x^2}{(0.280 M-x)}

Solving for x, we get:

x = 0.01346 M

So, the concentration of hydrogen ion at equilibrium is :

[H^+]=x=0.01346 M

The pH of the solution is ;

pH=-\log[H^+]=-\log[0.01346 M]=1.87

The pH of an 0.280 M HF solution is 1.87.

6 0
3 years ago
What must be part of a quantitative observation?
Likurg_2 [28]

Quantitative observations include numerical data. Ex: 32 degrees, 10 inches, etc.

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3 years ago
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