Explanation:
According to the ideal gas equation, PV = nRT.
where, P = pressure, V = volume
n = no. of moles, R = gas constant
T = temperature
Also, density is equal to mass divided by volume. And, no. of moles equals mass divided by molar mass.
Therefore, then formula for ideal gas could also be as follows.
P =
or, P =
Since, density is given as 0.789 g/ml which is also equal to 789 g/L (as 1000 mL = 1 L). Hence, putting the given values into the above formula as follows.
P =
=
= 525 atm
As two-liter soft drink bottle can withstand a pressure of 5 atm and the value of calculated pressure is 525 atm which is much greater than 5 atm.
Therefore, the soft drink bottle will obviously explode.
During this reaction, carbon dioxide<span> and water are converted into </span>glucose<span> and</span>oxygen<span>. The reaction requires light energy, which is absorbed by a green substance called </span>chlorophyll. Photosynthesis takes place in leaf cells. These containchloroplasts<span>, which are tiny objects containing </span>chlorophyll<span>.
Hope this helps~!
~Mistermistyeyed.</span>
2.2311 moles of gas are there in a 50. 0 l container at 22. 0 °c and 825 torrs.
<h3>What is an ideal gas?</h3>
An Ideal gas is a hypothetical gas whose molecules occupy negligible space and have no interactions, and which consequently obeys the gas laws exactly.
Assuming the gas is ideal, we can solve this problem by using the following equation:
PV = nRT
Where:
P = 825 torr ⇒ 825 / 760 = 1.08 atm
V = 50 L
n = ?
R = 0.082 atm·L·mol⁻¹·K⁻¹
T = 22 °C ⇒ 22 + 273.16 = 295.16 K
We input the data:
1.08 atm x 50 L = n x 0.082 atm·L·mol⁻¹·K⁻¹ x 295.16 K
And solve for n:
24.20312
n = 2.2311 mol
Hence, 2.2311 moles of gas are there in a 50. 0 L container at 22. 0 °c and 825 torrs.
Learn more about ideal gas here:
brainly.com/question/23580857
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Answer:
220.67 L
Explanation:
Using ideal gas equation as:
PV=nRT
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
From the equation, at constant P and T, V is directly proportional to moles
Thus, According to the reaction:
Methane gas and oxygen gas react in 2 : 3 ratio
So, Volume of methane gas = 662 L
Volume of oxygen gas = 331 L
Since, Volume of oxygen gas is less. It is the limiting reagent.
So,
3 L of oxygen gas forms 2 L of CO.
331 L of oxygen gas forms (2/3)*331 L of CO.
Volume of CO obtained = 220.67 L
Answer:
5.18.
Explanation:
<em>∵ [H₃O⁺][OH⁻] = 10⁻¹⁴.
</em>
[OH⁻] = 1.5 x 10⁻⁹ M.
∴ [H₃O⁺] = 10⁻¹⁴/[OH⁻] = 10⁻¹⁴/(1.5 x 10⁻⁹ M) = 6.66 × 10⁻⁶ M.
∵ pH = - log[H₃O⁺]
<em>∴ pH = - log(6.66 × 10⁻⁶ M) = 5.176 ≅ 5.18.</em>