1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Nutka1998 [239]
3 years ago
6

A chemist dilutes 185 of the 3.0 M solution with water until a new volume of 750 is obtained. Calculate the new concentration

Chemistry
1 answer:
svlad2 [7]3 years ago
7 0

Answer:

0.74M

Explanation:

Step 1 :

Data obtained from the question.

Initial concentration (C1) = 3M

Initial volume (V2) = 185mL

Final volume (V2) = 750mL

Final concentration (C2) =..?

Step 2:

Determination of the new concentration of the solution.

The new concentration of the solution can be obtained by using the dilution formula as shown below:

C1V1 = C2V2

3 x 185 = C2 x 750

Divide both side by 750

C2 = 3 x 185 / 750

C2 = 0.74M

Therefore, the new concentration of the solution is 0.74M

You might be interested in
When this reaction in equilibrium is heated, a red/brown color persists. what is true about this reaction? 2no2(
dimulka [17.4K]
NO₂ is a brown gas while N₂O₄ is colorless. If heating causes a brown color to persist, then this means that heating causes the reaction to shift backwards and produce NO₂. Therefore, the reaction must be exothermic.
7 0
3 years ago
Draw the bridged bromonium ion that is formed as an intermediate during the bromination of this alkene. include hydrogen atoms,
gogolik [260]
<h2>Answer</h2>

Bromination:

Any reaction or process in which bromine (and no other elements) are introduced into a molecule.

Bromonium Ion:

The bromonium ion is formed when alkenes react with bromine. When the π cloud of the alkene (acting as a nucleophile) approaches the bromine molecule (acting as an electrophile), the σ-bond electrons of Br2 are pushed away, resulting in the departure of the bromide anion.(2)

Mechanism:

Step 1:

In the first step of the reaction, a bromine molecule approaches the electron-rich alkene carbon–carbon double bond. The bromine atom closer to the bond takes on a partial positive charge as its electrons are repelled by the electrons of the double bond. The atom is electrophilic at this time and is attacked by the pi electrons of the alkene [carbon–carbon double bond]. It forms for an instant a single sigma bond to both of the carbon atoms involved (2). The bonding of bromine is special in this intermediate, due to its relatively large size compared to carbon, the bromide ion is capable of interacting with both carbons which once shared the π-bond, making a three-membered ring. The bromide ion acquires a positive formal charge. At this moment the halogen ion is called a "bromonium ion".

Step 2:

When the first bromine atom attacks the carbon–carbon π-bond, it leaves behind one of its electrons with the other bromine that it was bonded to in Br2. That other atom is now a negative bromide anion and is attracted to the slight positive charge on the carbon atoms. It is blocked from nucleophilic attack on one side of the carbon chain by the first bromine atom and can only attack from the other side. As it attacks and forms a bond with one of the carbons, the bond between the first bromine atom and the other carbon atoms breaks, leaving each carbon atom with a halogen substituent.

In this way the two halogens add in an anti addition fashion, and when the alkene is part of a cycle the dibromide adopts the trans configuration.

6 0
3 years ago
How many moles of chlorine (Cl) atoms are in a sample of 1.72 × 1022 atoms? 0.0286 mol Cl 35.0 mol Cl 1.03 × 1023 mol Cl 1.04 ×
kogti [31]

Given information : Sample of 1.72\times 10^{22} atoms

We need to find the moles of Chlorine in the given sample.

We can say that we need to find moles from the given atoms.

Relation between mole and atom is given by : 1 mole = 6.022\times 10^{23} atoms

Where 6.022\times 10^{23} is Avogadro number.

1.72\times 10^{22} atoms\times \frac{1 mole}{6.022\times 10^{23} atoms}

1.72\times 10^{22}\times \frac{1 mole}{6.022\times 10^{23}}

On solving the above equation , atoms(unit) gets cancelled out and we get 0.0286 mol.

In the given sample the moles of Chlorine (Cl) is 0.0286 mol , so option A is correct.

6 0
3 years ago
1-How many moles of NazCOs are in 10.0 ml of a 2.0 M solution?
Juliette [100K]

Answer:

Socratic app

Explanation:

it will help you

7 0
3 years ago
Design a synthesis of acetophenone from benzene or toluene. 1275q Part 1 out of 5 Choose the best option for the nucleophile pre
Trava [24]

Answer:

A Fridiel craft catalyst will convert benzene to acetophenone.

Permanganate catalyst can be used to convert toluene to acetophenone.

Explanation:

Benzene can be reduced to acetophenone by the addition of anhydrous aluminium chloride, AlCl₃

The mechanism is as follows:

Benzene + Acetyl choloride → acetophenone

To convert toluene to acetophenone, the following steps are necessary:

  • Oxidation of Toluene to Benzoic acid.

     This is done by refluxing toluene with alkaline potassium permanganate         (KMnO₄+ Na₂CO₃).

  • Benzoic acid is converted to Benzoyl chloride by treating with thioyl chloride and heating at about 80 ⁰C.
  • Benzoyl chloride is treated with methyl lithium to form Acetophenone.
5 0
3 years ago
Other questions:
  • Read the following story and then answer the questions.
    12·2 answers
  • The hydrogen ion concentration is 1 × 10-7. What is the ph of this solution?
    14·1 answer
  • What does the symbol H stand for
    7·1 answer
  • Will mark as Brainliest.
    8·1 answer
  • An unknown or changeable quantity is called a(n)...
    7·2 answers
  • What is the charge on an electron?<br> O-1<br> O 0<br> O +1<br> O +2
    6·1 answer
  • Why is the cell a basic unit of life?
    9·2 answers
  • How many kPa are in 2,150 mmHg?<br> 2.83 kPa<br> 287 kPa<br> 1.61 ´ 104 kPa<br> 2.18 ´ 105 kPa
    5·2 answers
  • Which bond is most polar?<br> ОА СО<br> ов So<br> Осно<br> ODNO
    11·1 answer
  • How many moles of CH3CH2Br are contained in 422 mL of 0.0950 M CH3CH2Br solution?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!