Answer:
Explanation:
Hello,
In this case, we can consider that the given heat of combustion is indeed the heat of reaction since it corresponds to the combustion of propane, which is computed by using the heat formation of all the involved species as shown below:
Thus, since the heat of formation of gaseous carbon dioxide is -393.5 kJ/mol, water -241.8 kJ/mol and oxygen 0 kJ/mol, the heat of formation of propane is:
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Answer:
yes
Explanation:
Solubility is an observation and no chemical reaction takes place. The composition of the compound/element is not changed.
- Hope that helped! Please let me know if you need further explanation.
A because the end result of this reaction is a radical created by the oxidation of an aromatic amine's or phenol's ring substituent. The hydroxyl group of a phenol acts as the ring substituent in this situation.
<h3>Which two enzyme types are required for the two-step process of converting cytosine to 5 hmC?</h3>
- The methyl group is transferred to cytosine in the first stage, and it is then hydroxylated in the second step.
- Therefore, a transferase and an oxidoreductase are the two groups of enzymes required.
<h3>Which kind of interaction between proteins and the dextran column material is most likely to take place?</h3>
- Hydrogen bonding because the glucose's OH would form an H-bond with any exposed polar side chains on a protein surface.
<h3>Two out of the four proteins would adhere to a cation-exchange column at what buffer pH? </h3>
- Only positively charged proteins can bind to a cation-exchange column, and this can only happen when the pH is lower than the pI.
- Proteins A and B would both be positively charged at pH 7.0.
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Answer:
Neither is affected
Explanation:
The reaction occurs as follows:
K₂Cr₂O₇ + Pb(NO₃)₂ → PbCr₂O₇ + 2K⁺ + 2NO₃⁻
That means per mole of reaction you will have two moles of both K⁺ and NO₃⁻.
But volume is also doubled, doing that concentration of spectator ions doesn't change.
Right answer: Neither is affected
I hope it helps!
Flourine.
You are very welcome
