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OlgaM077 [116]
3 years ago
7

What kind of relationship is it when a tree needs fungus to be present to grow normally

Physics
1 answer:
galina1969 [7]3 years ago
5 0
I think the question is describing the situation where the tree 
needs the fungus AND the fungus needs the tree.  Each one 
needs the other one in order to survive and grow normally.

This is called "symbiosis", or a "symbiotic" relationship.
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Can someone help me with this
yKpoI14uk [10]

bonded pairs of electrons, lone pairs of electrons.

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3 years ago
Intelligence test. If you get it right ,you are a critical thinker. You were in the garden,there are 34 people in the yard. You
bagirrra123 [75]

The riddle is solved by knowing that there is only one person left in the garden and that is you.

<h3>How many people are in the garden?</h3>

We are told that there were a total of 34 people in the yard. We do not know if these people are in the garden or somewhere around the yard. The next information we have is that a total of 30 persons were killed.

Since you killed them in the garden, the others may still be lurking somewhere in the yard thus there is only one person left in the garden and that is you.

Learn more about solving a riddle:brainly.com/question/25063408

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8 0
2 years ago
A computer base unit of mass 7.5 kg is dragged along a smooth desk. If the normal contact force is 23N and the tension in the ar
kramer
<span>If there isn't any force then the normal contact force will be 


N=m*g=7.5*9.81=73.58N 

which is 73.58-23=50.58N less 

so, there the person must pull at 23 degree upward 

break down the tension in two components, vertical and horizontal. 


vertical tension= 50.58=T*sin23 

T=50.58/sin23=129.45N</span>
7 0
3 years ago
Read 2 more answers
How much gravitational potential energy does a 45.2 kg object have when it is 21.9m above the ground?
Blizzard [7]

Answer:

Explanation:

The formula for gravitational potential energy is

Ep = m · g · h   Assuming that the acceleration is g = 10m/s²

Ep = 45.4 · 10 · 21.9 = 9,942.6 J

God is with you!!!

6 0
3 years ago
Calculate the speed of the car at each checkpoint by
lana66690 [7]

Answer: The speed at the first quarter checkpoint is 0.74 m/s. The speed at the second quarter checkpoint is 1.40 m/s. The speed at the third quarter checkpoint is 1.61 m/s. The speed at the finish line is 1.89 m/s.

Explanation: I did the assignment and got it correct :)

3 0
3 years ago
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