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Verizon [17]
3 years ago
9

When a virtual image is created in a plane mirrora. the image is upright.b. the image is located behind the mirror.c. reflected

rays diverge.d. all of the abovee. none of the above

Physics
1 answer:
zubka84 [21]3 years ago
4 0
<h2>Answer: all of the above</h2>

A plane mirror is a highly polished flat surface with a very high capacity to reflect incident light.

According to the figure attached:

1. The incident rays coming from the real object reach the mirror and  

2.are reflected following the law of Reflection.  

3.The prolongation of those reflected rays converge at a point that <u>does not coincide</u> with the actual position of the object. At that point the virtual image of the object is formed.  

4.Then, the reflected divergent rays are captured by our eye converging on the retina.

Now, the image is said to be <u>virtual</u> because it is a copy of the object that looks as if the object is behind the mirror and not in front of it or on the surface, but it is not really there. However, it can be seen when we focus it with our eyes.

In addition, the image formed is:

symmetrical, because apparently it is at the same distance from the mirror

the same size as the object.

upright, because it retains the same orientation as the object.

All these characteristics coincide with the first three options proposed in the question, so the correct option is d.

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An athlete at the gym holds a 3.0 kg steel ball in his hand. His arm is 70 cm long and has a mass of 4.0 kg. Assume, a bit unrealistically, that the athlete's arm is uniform.

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From the question we are told that

   The mass of the steel ball is  m  =  3.0 \  kg

    The length of arm is  l =  70 \ cm  = 0.7 \  m

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Given that the arm of the athlete is uniform them the distance from the shoulder to the center of gravity of the arm is mathematically represented as

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      \tau =  m_a * g * r  + m * g *  L

=>    \tau =  4 * 9.8 * 0.35 + 3 * 9.8 *  0.70

=>    \tau = 34.3 \  N\cdot m

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