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yan [13]
3 years ago
10

A train accelerates at -1.5 m/s2 for 10 seconds. If the train had an initial

Physics
1 answer:
Gnom [1K]3 years ago
7 0

Answer:

17 m/s

Explanation:

Using formula a = (v-u) /t

acceleration a =  -1.5 m/s2

final velocity v = unknown

initial velocity u = 32 m/s

time t = 10s

-1.5 = (v-32)/10

-15 = v - 32

-15 + 32 = v

v = 17 m/s

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<h3>Endothermic Reactions: </h3>

Endothermic reactions are the type chemical reaction in which the reactants absorb heat energy from the surroundings. The energy of reactants is more than the energy of product

<h3>Exothermic Reactions: </h3>

Exothermic reactions are the type of chemical reactions in which release of energy takes place in the form of heat or light. In an exothermic reaction, energy is released. The energy of the products is less than the energy of the reactants.

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The key word is "RELEASE". The reaction in which energy is released is the Exothermic reaction thus the Option B that is EXOTHERMIC REACTION is correct.

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It is asking that which process stores the energy that means it is asking which process undergoes endothermic reaction. The answer is Option C that is PHOTOSYNTHESIS is correct.

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tankabanditka [31]

Answer:

0.2528

Explanation:

To calculate the period we need the formula:

T=\frac{2\pi r^{3/2}}{\sqrt{GM}}

Where r is the radius of the moon, G is the universal constant of gravitation and M is the mass of mars.

The period of Phobos:

T_{p}=\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}

The period of Deimos:

T_{D}=\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}

The ratio of the period of Phobos and Deimos:

\frac{T_{p}}{T_{D}}=\frac{\frac{2\pi r_{p}^{3/2}}{\sqrt{GM}}}{\frac{2\pi r_{D}^{3/2}}{\sqrt{GM}}}

\frac{T_{p}}{T_{D}}=\frac{\sqrt{GM}2\pi r_{p}^{3/2}}{\sqrt{GM}2\pi r_{D}^{3/2}}

Most terms get canceled and we have:

\frac{T_{p}}{T_{D}}=\frac{r_{p}^{3/2}}{r_{D}^{3/2}}

According to the problem

r_{p}=9,378km\\r_{D}=23,459km

so the ratio will be:

\frac{T_{p}}{T_{D}}=\frac{(9,378)^{3/2}}{(23,459)^{3/2}}=\frac{908166.22}{3593058.125}=0.25275 ≈ 0.2528

the ratio of the period of revolution of Phobos to that of Deimos is 0.2528

8 0
3 years ago
Need help on this question ASAP please and thank youu!
hichkok12 [17]

Answer:

- 500kg

Explanation:

momentum calculator online

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