Question

A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following is the best approximation of the box’s acceleration?
120 m/s2
20 m/s2
1 m/s2
9 m/s2

Answer 1

Answer:

1 m/$s^{2}$

Explanation:

The Net Force refers to the sum of all forces acting on an object. Hence,

Net Force of box

= 20 + (-9.0)       [It is -9.0 as both forces are in different directions]

= 11.0 N

We also need to know that the net force on an object is equal to the product of the mass of the object and the acceleration of the object. Hence,

$F_{net} = ma$

11.0 = 12.0$a$

$a$ = 1 m/$s^{2}$ (nearest whole number)