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Tom [10]
3 years ago
14

A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i

s the best approximation of the box’s acceleration?
120 m/s2
20 m/s2
1 m/s2
9 m/s2
Physics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

1 m/s^{2}

Explanation:

The Net Force refers to the sum of all forces acting on an object. Hence,

Net Force of box

= 20 + (-9.0)       [It is -9.0 as both forces are in different directions]

= 11.0 N

We also need to know that the net force on an object is equal to the product of the mass of the object and the acceleration of the object. Hence,

F_{net} = ma

11.0 = 12.0a

a = 1 m/s^{2} (nearest whole number)

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Answer:

2m/s

Explanation:

5min × 60sec

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now,

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3 years ago
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If it is fixed at C and subjected to the horizontal 60-lblb force acting on the handle of the pipe wrench at its end, determine
pickupchik [31]

Answer:

τ = 132.773 lb/in² = 132.773 psi

Explanation:

b = 12 in

F = 60 lb

D = 3.90 in (outer diameter)  ⇒ R = D/2 = 3.90 in/2 = 1.95 in

d = 3.65 in (inner diameter)  ⇒ r = d/2 = 3.65 in/2 = 1.825 in

We can see the pic shown in order to understand the question.

Then we get

Mt = b*F*Sin 30°

⇒ Mt = 12 in*60 lb*(0.5) = 360 lb-in

Now we find ωt as follows

ωt = π*(R⁴ - r⁴)/(2R)

⇒ ωt = π*((1.95 in)⁴ - (1.825 in)⁴)/(2*1.95 in)

⇒ ωt = 2.7114 in³

then the principal stresses in the pipe at point A is

τ = Mt/ωt ⇒ τ = (360 lb-in)/(2.7114 in³)

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7 0
4 years ago
Match Newton's laws with their descriptions. 1. Every applied force is opposed by an equal force. 2 .A force must be applied to
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• What are common questions, concerns, practices, and experiences across various world religions? Include indigenous religions i
faltersainse [42]

<u>Answer:</u>

<em>They are a lot of religions and faiths across the globe. </em>

<u>Explanation:</u>

There are  a lot of monotheistic and polytheistic religions across the world that took origin at different points in the past.

Some of them are:

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5 0
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