1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Tom [10]
3 years ago
14

A student pushes a 12.0 kg box with a horizontal force of 20 N. The friction force on the box is 9.0 N. Which of the following i

s the best approximation of the box’s acceleration?
120 m/s2
20 m/s2
1 m/s2
9 m/s2
Physics
1 answer:
wolverine [178]3 years ago
8 0

Answer:

1 m/s^{2}

Explanation:

The Net Force refers to the sum of all forces acting on an object. Hence,

Net Force of box

= 20 + (-9.0)       [It is -9.0 as both forces are in different directions]

= 11.0 N

We also need to know that the net force on an object is equal to the product of the mass of the object and the acceleration of the object. Hence,

F_{net} = ma

11.0 = 12.0a

a = 1 m/s^{2} (nearest whole number)

You might be interested in
A particle having a speed of 0.87c has a momentum of 10-16 kg·m/s. what is its mass?
cupoosta [38]
The momentum p of a moving particle is the product between its mass, m, and tis velocity, v:
p=mv
In our problem, we know p=10^{-16}~Kg \cdot m/s and v=0.87c=0.87\cdot 3\cdot10^8~m/s=2.61\cdot 10^8~m/s, and using the relationship mentioned above, we can find the mass m of the particle:
m= \frac{p}{v} =3.8\cdot10^{-25}~Kg
8 0
3 years ago
PLEASE HELP IM DESPERATE- what is the same and different about these two parabolas
krok68 [10]
One is bigger than the other and they are the same shape
7 0
2 years ago
A spacecraft is fueled using hydrazine (N2H4; molecular weight of 32 grams per mole [g/mol]) and carries 1640 kilograms [kg] of
Sauron [17]

Answer:

The value is t = 689.029 \  hours

Explanation:

From the question we are told that

The molar mass of hydrazine is Z =  32 g/mol = \frac{32}{1000} = 0.032 \  kg/mol

The initial temperature is T_i  =  -186 ^o F = (-186-32) *\frac{5}{9} +273.15 = 152\ K

The final temperature is T_f  =  78 ^o F = (78-32) *\frac{5}{9} +273.15 = 298.7 \ K

The specific heat capacity is c_h  =  0.099 [kJ/(mol K)] = 0.099 *10^3 J/(mol/K)

The power available is P = 300 \ W

The mass of the fuel is m =   1640 \  kg

Generally the number of moles of hydrazine present is

n  =  \frac{m}{Z}

=> n  =  \frac{1640}{= 0.032}

=> n  =  51250 \ mol

Generally the quantity of heat energy needed is mathematically represented as

Q =  n * c_h * (T_f -T_i)

=> Q =  51250  * 0.099 *10^3  * (298.7 - 152)

=> Q =  7.441516913 * 10^{8} \  J

Generally the time taken is mathematically represented as

t =  \frac{Q}{P}

=> t =  \frac{7.441516913 * 10^{8} }{300}

=> t = 2480505.6377 s

Converting to hours

t = \frac{2480505.6377}{3600}

=> t = 689.029 \  hours

6 0
3 years ago
The pressure in an automobile tire depends on the temperature of the air in the tire. When the air temperature is 25°C, the pres
12345 [234]

Answer:0.0704 kg

Explanation:

Given

initial Absolute pressure(P_1)=210+101.325=311.325

T_1=25^{\circ}\approx 298 K

V=0.025 m^3

T_2=50^{\circ}\approx 323 K

as the volume remains constant therefore

\frac{P_1}{T_1}=\frac{P_2}{T_2}

\frac{311.325}{298}=\frac{P_2}{323}

P_2=337.44 KPa

therefore Gauge pressure is 337.44-101.325=236.117 KPa

Initial mass m_1=\frac{P_1V}{RT_1}=\frac{311.325\times 0.025}{0.0287\times 298}

m_1=0.91 kg

Final mass m_2=\frac{P_2V}{RT_2}=\frac{311.325\times 0.025}{0.0287\times 323}

m_2=0.839

Therefore m_1-m_2=0.91-0.839=0.0704 kg of air needs to be removed to get initial pressure back

4 0
3 years ago
Find the length (in m) of an organ pipe closed at one end that produces a fundamental frequency of 494 Hz when air temperature i
elena-14-01-66 [18.8K]

Answer:

0.173 m.

Explanation:

The fundamental frequency of a closed pipe is given as

fc = v/4l .................. Equation 1

Where fc = fundamental frequency of a closed pipe, v = speed of sound  l = length of the pipe.

Making l the subject of the equation,

l = v/4fc ................ Equation 2

also

v = 331.5×0.6T ................. Equation 3

Where T = temperature in °C, T = 18.0 °c

Substitute into equation 3

v = 331.5+0.6(18)

v = 331.5+10.8

v = 342.3 m/s.

Also given: fc = 494 Hz,

Substitute into equation 2

l = 342.3/(4×494)

l = 342.3/1976

l =0.173 m.

Hence the length of the organ pipe = 0.173 m.

7 0
3 years ago
Other questions:
  • A string is wrapped several times around the rim of a small hoop with radius 8.00 cm and mass 0.180 kg. The free end of the stri
    12·2 answers
  • The Hubble Space Telescope (HST) orbits 569 km above Earth’s surface. If HST has a tangential speed of 7,750 m/s, how long is HS
    8·2 answers
  • What is an example of volume
    7·1 answer
  • Plants release water vapor into the atmosphere through the process called _____.
    7·2 answers
  • Sound waves travel fastest through<br> solids<br> gasses<br> liquids
    12·2 answers
  • Salma is riding her bicycle. She rides 25.6 kilometers in 4 hours. What is her speed?
    8·1 answer
  • Which scientist developed the equation of wave mechanics? de broglie schr��dinger bohr chadwick?
    14·2 answers
  • BRAINLIEST WILL BE GIVEN!!!!! After communicating the information you requested above, he pushes the sled a total distance of 50
    6·1 answer
  • What is your worldview? Explain?
    9·1 answer
  • Need Help
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!