Data is inappropriate
here, we need gauge of the wire i.e., diameter of the wire, so that we calculate the resistance by using the formula
R = ρl/A
where R= resistance ; Ω
l = length of wire ; m
A = area of wire ; m²
ρ = resistivity ; Ω-m
But in general ohms law is
V = I R
R = V/I ;
but here we also calculate "R" from length of wire in which the current is flowing.
I hope it is helpful to you.
Answer:
μ=0.151
Explanation:
Given that
m= 3.5 Kg
d= 0.96 m
F= 22 N
v= 1.36 m/s
Lets take coefficient of kinetic friction = μ
Friction force Fr=μ m g
Lets take acceleration of block is a m/s²
F- Fr = m a
22 - μ x 3.5 x 10 = 3.5 a ( take g =10 m/s²)
a= 6.28 - 35μ m/s²
The final speed of the block is v
v= 1.36 m/s
We know that
v²= u²+ 2 a d
u= 0 m/s given that
1.36² = 2 x a x 0.96
a= 0.963 m/s²
a= 6.28 - 35μ m/s²
6.28 - 35μ = 0.963
μ=0.151
Answer:
a♦1 E_average = n E₀ / 2
, b) E_average= infinity
Explanation:
The energy values form an arithmetic series, whose sum is
S = n (a₁ + aₙ) / 2 = n (2a₁ + (n-1) r)/ 2
Where n is the number of terms, a₁ is the first term, aₙ the last term and r is the difference between two consecutive numbers in the series
r = 2E₀ - 0 = 2E₀
Therefore the sum is
S = n (0 + n E₀) / 2
S = n² E₀ / 2
The average value is
E_average = S / n
E_average = n E₀ / 2
b) the case of harmonic oscillation
We have two possibilities.
- if we take a finite number and terms gives the same previous value
- If we take an infinite number of fears the series gives infinity and the average is also infinite
E_average= infinity
Answer: Mass and kinetic energy have a positive relationship, which means that as mass increases, kinetic energy increases, if all other factors are held constant
Explanation:
Answer:
a) It moved to a lower potential
b) ΔФ = - 86.28 Volt
Explanation:
The energy of an charged particle and the electric potential are related by the potential al kinetic energies:
If we consider an electron:
m = 9.10938*10^-31 Kilogram
e = 1.60218*10^-19 Coulomb
And the potential diference may be calculed by:
Replacing all the values we get:
ΔФ = - 86.28 (Kilogram Meter^2)/(Coulomb Second^2) = -86.28 Volts
