Explanation:
We need to calculate the speed of light in each materials
(I). Gallium phosphide,
The index of refraction of Gallium phosphide is 3.50
Using formula of speed of light
....(I)
Where, 
= index of refraction
c = speed of light
Put the value into the formula
(II) Carbon disulfide,
The index of refraction of Gallium phosphide is 1.63
Put the value in the equation (I)
(III). Benzene,
The index of refraction of Gallium phosphide is 1.50
Put the value in the equation (I)
Hence, This is the required solution.
Bohr’s model showed that electron orbits had distinct radii.
Given data
efficiency (η) = 65 %
= 0.65
Machine provides (Work done by the machine) = 1300 × 50
= 65000 J
efficiency (η) = work done by the machine ÷ work supplied to the machine
0.65 = 65000 ÷ Input work
Input work = 100000 J
= 100 KJ
By definition we know that the distance is equal to the speed by time
d = v * t
Clearing the time we have
t = d / v
for conservation of energy. we have to for every attempt
mgh = (1/2) mv ^ 2
Clearing the speed
v = Root (2gh)
Then, substituting
t = d / v
t = h / (Root (2gh)
We conclude that the time is the same since it depends on the height of the table to the floor.
