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Kryger [21]
3 years ago
14

if a 40 kg person is accelerating at m/s^2,then the magnitude of force acting on him or her 400 N? true or false

Chemistry
1 answer:
Mrac [35]3 years ago
4 0
<span> F = ma = 40kg * 10m/s^2 = 400 kg-m/s^2 = 400N</span>
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2 HCl + Na2SO4 &gt; 2 NaCl + H2SO4
Cerrena [4.2K]

Answer:

15

Explanation:

8 0
2 years ago
How many moles is 22.4 liters of oxygen gas at standard temperature and pressure represent
makkiz [27]

Answer:

So 1 mole

Explanation:

PV = nRT

P = Pressure atm

V = Volume L

n = Moles

R = 0.08206 L·atm·mol−1·K−1.

T = Temperature K

standard temperature = 273K

standard pressure = 1 atm

22.4 liters of oxygen

Ok so we have

V = 22.4

P = 1 atm

PV = nRT

n = PV/RT

n = 22.4/(0.08206 x 273)

n  = 22.4/22.40

n = 1 mole

7 0
3 years ago
At a certain temperature, the solubility of n2 gas in water at 3.08 atm is 72.5 mg of n2 gas/100 g water . calculate the solubil
8090 [49]

According to Henry's law, solubility of solution is directly proportional to partial pressure thus,

\frac{S_{1}}{P_{1}}=\frac{S_{2}}{P_{2}}

Solubility at pressure 3.08 atm is 72.5/100, solubility at pressure 8 atm should be calculated.

Putting the values in equation:

\frac{0.725}{3.08}=\frac{S_{2}}{8}

On rearranging,

S_{2}=\frac{0.725\times 8}{3.08}=1.88

Therefore, solubility will be 1.88 mg of N_{2} gas in 1 g of water or, 188 mg of tex]N_{2}[/tex] gas in 100 g of water.

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3 years ago
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2 years ago
Read 2 more answers
Suppose you are titrating vinegar, which is an acetic acid solution
kotegsom [21]

Answer:

0.373 M

Explanation:

The balanced equation for the reaction is given below:

HC2H3O2 + NaOH —> NaC2H3O2 + H2O

From the balanced equation above, the following were obtained:

Mole ratio of the acid, HC2H3O2 (nA) = 1

Mole ratio of the base, NaOH (nB) = 1

Next, we shall write out the data obtained from the question. This include:

Volume of base, NaOH (Vb) = 32.17 mL

Molarity of base, NaOH (Mb) = 0.116 M

Volume of acid, HC2H3O2 (Va) = 10 mL

Molarity of acid, HC2H3O2 (Ma) =..?

The molarity of the acid solution can be obtained as follow:

MaVa/MbVb = nA/nB

Ma x 10 / 0.116 x 32.17 = 1

Cross multiply

Ma x 10 = 0.116 x 32.17

Divide both side by 10

Ma = (0.116 x 32.17) /10

Ma = 0.373 M

Therefore, the concentration of the acetic acid is 0.373 M.

8 0
3 years ago
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