Answer:
the moment of inertia of the merry go round is 38.04 kg.m²
Explanation:
We are given;
Initial angular velocity; ω_1 = 37 rpm
Final angular velocity; ω_2 = 19 rpm
mass of child; m = 15.5 kg
distance from the centre; r = 1.55 m
Now, let the moment of inertia of the merry go round be I.
Using the principle of conservation of angular momentum, we have;
I_1 = I_2
Thus,
Iω_1 = I'ω_2
where I' is the moment of inertia of the merry go round and child which is given as I' = mr²
Thus,
I x 37 = ( I + mr²)19
37I = ( I + (15.5 x 1.55²))19
37I = 19I + 684.7125
37I - 19 I = 684.7125
18I = 684.7125
I = 684.7125/18
I = 38.04 kg.m²
Thus, the moment of inertia of the merry go round is 38.04 kg.m²
Answer:
if one wave has a negative displacement, the displacements would be opposite each other, so the displacement where the waves overlap is less than it would be due to either of the waves separately.
-causes a moment where the net displacement of the medium is zero. energy of waves hasn't vanished, but it is in the form of the kinetic energy of the medium
-then both emerge unchanged
Explanation:
point y is in the interior of xwz. given that and are opposite rays and mxwy4(mywz), mywz = 36°
Opposite rays:- Opposite rays are the rays, which shares a common initial point, but points towards opposite directions. Angle between two opposite rays is 180°.
According to the question,
m∠XWY = 4(m∠YWZ) (Given)
As the two rays WX and WZ are opposite rays, the initial points of those are same. Here in the question, it is W.
∴∠XWZ = 180°
∴m∠XWY + m∠YWZ = 180°
⇒ 4(m∠YWZ) + m∠YWZ = 180°
⇒ 5(m∠YWZ) = 180°
⇒ m∠YWZ = 180°/5
⇒ m∠YWZ = 36°
Thus we can conclude that, m∠YWZ = 36°.
To know more about opposite rays refer below link:
brainly.com/question/28216147
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