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PilotLPTM [1.2K]
3 years ago
9

Which theory of the origin of the moon would be most supported if the moon had an irregular shape, like an asteroid? impact theo

ry co-formation theory capture theory synchronous theory
Physics
2 answers:
RideAnS [48]3 years ago
4 0

Answer:This would be the capture theory.

Explanation:

Fiesta28 [93]3 years ago
3 0
<span>Its the impact theory.
It suggests that the moon resulted from the collision of two protoplanets, or embryonic worlds. One of those was the just-forming Earth, and the other was a Mars-size object called Theia. The moon then coalesced from the debris, thus giving it its irregular shape.</span>
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a bus starting from rest moves with a uniform acceleration of 0.1 metre per second square for 2 minutes find the speed acquired
blondinia [14]
S ?
U 0m/s
V ?
A 0.1m/s^2
T 2min (120 sec)

S=ut+0.5at^2
S=0(120 sec)+0.5(0.1m/s^2)(120 sec)^2
S=720m

Distance double 720m*2=1440m

V^2=u^2+2as
V^2=(0)^2+2(0.1 m/s^2)(1440m)
V^2=288
V= square root of 288=12 root 2=16.97 to 2 decimal places
6 0
3 years ago
In the Bohr model of the hydrogen atom, the speed of the electron is approximately 2.2 106 m/s.
Murrr4er [49]

The central force acting on the electron as it revolves in a circular orbit is 9.52 \times 10^{-8} \ N.

The given parameters;

  • <em>speed of electron, v = 2.2 x 10⁶ m/s</em>
  • <em>radius of the circle, r = 4.63 x 10⁻¹¹ m</em>

<em />

The central force acting on the electron as it revolves in a circular orbit is calculated as follows;

F = \frac{M_e v^2}{r} \\\\

where;

M_e is mass of electron = 9.11 x 10⁻³¹ kg

F = \frac{(9.11 \times 10^{-31}) \times(2.2\times 10^6)^2 }{4.63 \times 10^{-11}} \\\\F = 9.52 \times 10^{-8} \ N

Thus, the central force acting on the electron as it revolves in a circular orbit is 9.52 \times 10^{-8} \ N.

Learn more about centripetal force here:brainly.com/question/20905151

8 0
2 years ago
An Astronaut lands on an Earthlike planet and drops a small lead ball with a mass from the top of her spaceship. The point of re
bearhunter [10]

First we have to find out the gravity on that planet. We use Newton second equation of motion. It is given as,

s = ut +(gt^2)/2

Distance s = 25m

Time t = 5 s

Velocity u = 0

By putting these values,

25 = 1/2.g.(5)²

g = 2

So the gravity on that planet is 2. Lets find out the weight of the astronaut.

Mass of the astronaut on earth m = 80 kg

Weight of astronaut on earth W = mg = (80)(9.8) = 784 N

Weight of astronaut on earth like planet = (80)(2) = 160 N

x = 160N

5 0
2 years ago
Simple curiosity is not a legitimate reason to complete a scientific investigation.
jok3333 [9.3K]
True......I would say...
7 0
3 years ago
Read 2 more answers
A student wants to determine the coefficient of static friction μ between a block of wood and an adjustable inclined plane. Of t
Cloud [144]

Answer:

A protractor to measure the angle of the inclined plane with the horizontal

Explanation:

The student needs to lift the free end of the adjustable inclined plane until the object barely starts sliding, and measure the angle at which such happens. At that point, the force of friction equals the component of the weight in the direction of the incline. That is:

f=\mu\,* N = \mu * m g\, cos(\theta)

and  w_{//}= m\,g\,sin(\theta)

Then  

f = w_{//}\\\mu *\,m \,g\,cos(\theta) = m\,g\,sin(\theta)\\\mu = tan(\theta)

and therefore, the coefficient of static friction is fully determined just by calculating the tangent of the angle that the incline forms with the horizontal.

Then the only extra instrument needed is a protractor to measure the angle.

7 0
3 years ago
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