<span> Displacement of the medium perpendicular to the direction of propagation of the wave. that would be your answer</span>
<span>Answer:
Well, let's start by finding the pressure due to the "extra" height of the mercury.
p = 1.36e4 kg/m³ · (0.105m - 0.05m) · 9.8m/s² = 7330 N/m² = 7330 Pa
The pressure at B is clearly p_b = p_atmos = p_gas + 7330 Pa
The pressure at A is p_a = p_gas = p_atmos - 7330 Pa
c) 1 atm = 101 325 Pa
Then p_gas = 101325 Pa - 7330 Pa = 93 995 Pa</span>
The correct answer would be C. three half lives.
Answer:
d. Potential energy is converted to kinetic energy; the kinetic energy is then converted into the work of bringing the body to a stop.
Explanation:
- At the beginning of the falls, when the person is still at a certain height h, the person has gravitational potential energy:
U = mgh
where m is the mass of the person, g the acceleration due to gravity, h the height above the ground.
- As the person falls down, h decreases, so the potential energy decreases; according to the law of conservation of energy, potential energy is converted into kinetic energy, since the speed of the person increases:

where v is the speed.
- Just before hitting the ground, all the potential energy has been converted into kinetic energy
- When the person hits the ground, he/she comes to a stop: so work is done by the ground on the person, because the ground applied a force required to stop the person, and the kinetic energy "lost" by the person is equal to the work done by the ground to bring the body to a stop.
Let's take the initial mass of the object = m
velocity = v
initial KE = 1/2 mv² = 0.5mv²
Now the velocity is trippled
V = 3v
mass is cut in half
M = 0.5m
final KE = 1/2 MV² = 1/2 x (0.5m) x (3v)² =9/4 mv² = 2.25 mv²
Change in KE = 2.25mv² - 0.5mv² = 1.75mv²
% change = (Change in KE/initial KE) x 100
= (1.25mv²/0.5mv²) x 100
= (1.25/0.5) x 100
=250%
Change in kinetic energy is 250%
Hope it helps!