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Serhud [2]
2 years ago
13

Your chances of getting into a collision when talking on a cell phone _________: A. Double B. Triple C. Quadruple D. Remain the

same
Physics
1 answer:
Anit [1.1K]2 years ago
3 0

Answer:

C. Quadruple

Explanation:

¨Drivers who are talking on the phone, even on a hands-free device, are up to four times more likely to be involved in a crash.¨

I hope this helps! Have a great day!

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Exercise b) 1) Fill in the blanks with the appropriate word: a) The pressure exerted by the air in atmosphere is called b) Press
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Answer:

atmospheric pressure

b)

c)increases

d) ....

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3 years ago
A model rocket is shot directly upward, rises to its maximum height and then returns to its launch position in 10.0 s. Assuming
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d. 49.0 m/s

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3 0
3 years ago
An apple is thrown across the cafeteria with a force of 10 N and at an acceleration of 6 m/s2. What is the mass of the apple? ..
Komok [63]

Answer:

Explanation:

F = m * a

The apple's acceleration is not influenced by the acceleration due to gravity for this question.  In real life it most certainly is influenced by gravity.

F = m * a

F = 10 Newtons.

a = 6 m/s^2

m = 10/6 = 1.66 kg. Mighty  large apple

7 0
4 years ago
Question 9 Unsaved A 680-Hz sound wave travels at 340 m/s in air, with a wavelength of 0.5 m. 5 m. 50 m. 500 m. none of the abov
ale4655 [162]

The correct option is 0.5 M

Calculation

Wavelength is defined as the ratio of velocity of a wave to its frequency. It is measure in meters. Mathematically, wavelength is given by the following formula:

Wavelength = wave velocity / frequency

From the details given in the question,

Wavelength =?

Velocity = 340 m/s

Frequency = 680 HZ

Wavelength = 340 /680 = 0.5

Therefore, wavelength = 0.5 M

5 0
3 years ago
Read 2 more answers
A 240-volt, 2-amp motor is connected to a three-wire, 120/240-volt system. Connected between the black wire and neutral are four
pantera1 [17]

Answer:

(i)The current flow in black wire = 9.67 A (ii) The current low in the red wire is 9.68 A (iii) The current flow in neutral wire is  15.36 A (iv) when 240 volt were disconnected current  in black wire is 7.68 A (v) when 240 volt were disconnected current in red wire is 7.68 A (vi) 15.36 A (vii) 6.34 (viii) 9.68 A (ix) 12.02 A

Explanation:

Solution

The current drawn by one amp is

I =P/V

I =200/120

I= 1.67 A

(i) The current flow in the black wire  is

IBK = 4 * 1.67 A + 1A + 2A

IBK = 9.67 A

(ii) Current flow in the red wire is

IRD = 3 * 1.67 A + 1.67 A + 1A + 2A

= 8.68A + 1 A = 9.68 A

Note: Kindly find an attached copy of part of the solution to the given question above.

6 0
3 years ago
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