Explanation:
The vertical component = 10sin30° = 5.0N.
Answer:
a) 425.6 K = 152.6 degree Celsius
b) 678.6 square centimeter
Explanation:
Initial enthalpy = Final enthalpy
m(h1 + v1^2/2) = m(h2 + v2^2/2)
(h1 + v1^2/2) = (h2 + v2^2/2)
h 2 = (h1 + v1^2/2) - (v2^2/2)
h 2 = 400.98 + (230^2 – 30^2)/2 * 10^-3
= 426.98 KJ/Kg
T2 = T1’ + (T2’ -T1’)(h2-h1’)/( h2’-h1’)
T2 = 420 + (430-420)(431.43-421.26)(426.98-421.26)/(431.43 – 421.26)
T2 = 425.6 K = 152.6 degree Celsius
Area = mRT2/P2V2
Area = (600/60*60*1) *0.287*425.6/(100*30) *10^4
Area = 678.6 square centimeter
Boyle's law<span> is a gas </span>law<span>, stating that the pressure and volume of a gas have an inverse relationship , when temperature is held constant. That is PV = constant. Therefore, (PV)initial = (PV)final. 42x11 = 9x P(final). P(final) = 42x11/9 = 51.34kPa. </span>
The conversion that should be made for this certain problem would be from miles to feet and from hours to second. The conversion of miles to feet would have a factor of 5280. For hours to second the factor would be 3600. Hope this answers the question.
Answer:
The gravitational force is 3.509*10^17 times larger than the electrostatic force.
Explanation:
The Newton's law of universal gravitation and Coulombs law are:

Where:
G= 6.674×10^−11 N · (m/kg)2
k = 8.987×10^9 N·m2/C2
We can obtain the ratio of these forces dividing them:
--- (1)
The mass of the moon is 7.347 × 10^22 kilograms
The mass of the earth is 5.972 × 10^24 kg
And q1=q2=Na*e=(6.022*10^23)*(1.6*10^-19)C=9.635*10^4 C
Replacing these values in eq1:

Therefore

This means that the gravitational force is 3.509*10^17 times larger than the electrostatic force, when comparing the earth-moon gravitational field vs 1mol electrons - 1mol protons electrostatic field