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marshall27 [118]
3 years ago
12

BER:

Chemistry
1 answer:
vagabundo [1.1K]3 years ago
7 0
C. global warming
hope this helps!
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At what temperature will 0.654 moles of helium gas occupy 12.30 liters at 1.95 atmospheres?
DedPeter [7]

Answer:

447,25k

Explanation:

According to the ideal gas law

PV=nRT

Where:

P: is the pressure of the gas in atmospheres.

V: is the volume of the gas in liters.

n: number of moles of the gas

R: ideal gas constant

T: absolute temperature of the gas in kelvin

now using:

T=\frac{PV}{nR}\\ \\T=\frac{12,3L.1,95atm}{0,654mol.0,082(L.atm/K.mol)}\\ \\T=447,25K

3 0
3 years ago
In general, when the addition of an unsymmetrical electrophilic reagent to an unsymmetrical alkene forms the product predicted b
Tju [1.3M]

It is formed via the more/most stable carbocation.

What justification exists for Markovnikov's Rule?

A carbocation is created as a result of the protonation of the alkene by the protic acid. The carbocation that has the most alkyl substituents on its carbon holds the positive charge, making it the most stable carbocation. As a result, the addition of the halide to the carbon that has fewer hydrogen substituents makes up the majority of the product.

Markovnikov's rule

According to the Markovnikov rule, a proton is added to the carbon atom with the greatest number of hydrogen atoms connected in addition to processes involving alkenes or alkynes.

Anti-Markovnikov Rule

According to the Anti-Markovnikov Rule, in addition to reactions between alkenes or alkynes, The carbon atom with the fewest hydrogen atoms linked to it receives the proton.

Learn more about Carbocation here:-

brainly.com/question/14363695

#SPJ4

7 0
2 years ago
What is the pH of a Koh solution that has [H+]=1.87×10^-13M
xenn [34]
PH=-log[H⁺]
pH=-log(1.87×10⁻¹³)
pH=12.72

I hope this helps.  Let me know if anything is unclear.
7 0
3 years ago
Read 2 more answers
Which of the following parts of decomposing living organisms are usually not preserved as fossils?
Lynna [10]
Skin and organs would be correct

7 0
3 years ago
Read 2 more answers
A solution contains 0.115 mol h2o and an unknown number of moles of nacl. the vapor pressure of the solution at 30°c is 25.7 tor
Valentin [98]
According to Raoult's low:
We will use this formula: Vp(Solution) = mole fraction of solvent * Vp(solvent)
∴ mole fraction of solvent = Vp(Solu) / Vp (Solv)
when we have Vp(solu) = 25.7 torr & Vp(solv) = 31.8 torr 
So by substitution:
∴ mole fraction of solvent = 25.7 / 31.8 =0.808 
when we assume the moles of solute NaCl = X 
and according to the mole fraction of solvent formula:
mole fraction of solvent = moles of solvent / (moles of solvent + moles of solute)
by substitute:
∴ 0.808 = 0.115 / (0.115 + X)
 So X (the no.of moles of NaCl) = 0.027 m
8 0
3 years ago
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