All categories

2 years ago

In triangle ABC, the measure of angle A is 90 ° . Angle B is congruent to angle C. What is the measure of angle B in degrees?

Mathematics

1 answer:

densk [106]2 years ago

3 0

Answer: 45 degrees

Step-by-step explanation:

You might be interested in

Which of the following is best described as a three-dimensional solid consisting of a base that can be any polygon a point not i

Harman [31]

Answer:

Option D

Pyramid

Step-by-step explanation:

The clause that gave away the answer is "three-dimensional solid consisting of a base that can be any polygon"

Scanning through the options, we can see that the only option that fits the description is the pyramid.

The pyramid is the only three-dimensional shape amongst the options that can take any polygon as a base.

The other options get screened out here.

A cube must have a square base.

A triangular prism must have a triangular base

A rectangular prism must have a rectangular base

Thus, option D: The Pyramid is the correct answer.

3 0

3 years ago

What is the simplified form of 3135?

monitta

Answer:

Step-by-step explanation:

yes

6 0

3 years ago

Is negative 17/24th bigger or smaller than negative 11/12

Triss [41]

It would be smaller because 11/12 = 22/24

5 0

3 years ago

Solve for n. 2n-3/5 = 5.

dangina [55]

$\dfrac{2n-3}{5}=5\\\\
2n-3=25\\\\
2n=28\\\\
n=14$

7 0

3 years ago

Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}$

So we have

$\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}$

8 0

3 years ago