Answer:
0.687 m/s
Explanation:
Initial energy = final energy
1/2 mu² = mgh + 1/2 mv²
1/2 u² = gh + 1/2 v²
Given u = 2.00 m/s, g = 9.8 m/s², and h = 0.180 m:
1/2 (2.00 m/s)² = (9.8 m/s²) (0.180 m) + 1/2 v²
v = 0.687 m/s
The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.
<h3>How to solve for the time interval</h3>
We have y = 0.175
y(x, t) = 0.350 sin (1.25x + 99.6t) = 0.175
sin (1.25x + 99.6t) = 0.175
sin (1.25x + 99.6t) = 0.5
99.62 = pi/6
t1 = 5.257 x 10⁻³
99.6t = pi/6 + 2pi
= 0.0683
The time interval that is between the first two instants when the element has a position of 0.175 is 0.0683.
b. we have k = 1.25, w = 99.6t
v = w/k
99.6/1.25 = 79.68
s = vt
= 79.68 * 0.0683
= 5.02
Read more on waves here
brainly.com/question/25699025
#SPJ4
complete question
A transverse wave on a string is described by the wave function y(x, t) = 0.350 sin (1.25x + 99.6t) where x and y are in meters and t is in seconds. Consider the element of the string at x=0. (a) What is the time interval between the first two instants when this element has a position of y= 0.175 m? (b) What distance does the wave travel during the time interval found in part (a)?
Do you not understand how to solve for the answer?
Answer:
Maharashtra - mashru or himroo / dhoti and lugda
Gujarat - patola / ghagra choli
Punjab - pat / kurta and pajama
Odisha - ikat / Sadi
West Bengal - tossa / kurta
Karnataka - Mysore silk / mundu
Answer:
orce or acceleration b. Ms. Sunderland finally decided to take this seriously and put both hands on the rope and applied a 1000 N force to the left, while Jared and James still struggled with their 300 N force to the right. What is ... 150 more force. 10. During 5th period Dylan resisted the forces applied by her classmates in a ...
Explanation:
