Identical particles, each with energy E, are incident on the following four potential energy
1 answer:
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The radio waves are electromagnetic wave, so it travels with velocity of light i.e .
We can use the relation between frequency, wavelength and speed as
Here c is speed of light, is wavelength and f is frequency and its value is given 99.90 FM, it is actually in megahertz (i.e 99.90 MHz).
Therefore,
.
Thus, the broadcast wavelength of the given radio station is 3.003 m.
Answer:
Yes, the car driver is exceeding the given limit.
Explanation:
<u>Given:</u>
- Speed of the car, v = 38.0 m/s.
- Speed limit of the highway,
We know,
1 mi = 1.60934 km.
1 km = 1000 m.
Therefore, 1 mi = 1.60934 × 1000 m = 1609.34 m.
1 hour = 60 minutes.
1 minute = 60 seconds.
Therefore, 1 hour = 60 × 60 seconds = 3600 seconds.
Using these values,
Therefore,
Clearly,
which means, the car driver is exceeding the given speed limit.
Answer:
The velocity is
Explanation:
From the question we are told that
The first distance is
The first speed is
The second distance is
The second speed is
Generally the time taken for first distance is
The time taken for second distance is
The total time is mathematically represented as
=>
=>
Generally the constant velocity that would let her finish at the same time is mathematically represented as
=>
=>