Answer: Concentration of
in the equilibrium mixture is 0.31 M
Explanation:
Equilibrium concentration of
= 0.729 M
The given balanced equilibrium reaction is,

Initial conc. x 0 0
At eqm. conc. (x-2y) M (y) M (3y) M
The expression for equilibrium constant for this reaction will be:
3y = 0.729 M
y = 0.243 M
![K_c=\frac{[y]\times [3y]^3}{[x-2y]^2}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5By%5D%5Ctimes%20%5B3y%5D%5E3%7D%7B%5Bx-2y%5D%5E2%7D)
Now put all the given values in this expression, we get :



concentration of
in the equilibrium mixture = 
Thus concentration of
in the equilibrium mixture is 0.31 M
Answer:
Top left: RR Top right: Rr Bottom left: Rr Bottom right: rr
Explanation:
if both parents are heterozygous then the table will always look like this. the chances of the offspring being heterozygous are 50%. the offspring has a 25% chance of having two recessive traits and a 25% chance of having two dominant traits.
Answer: The volume the gas will occupy at STP is 6.9 L
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,

where,
= initial pressure of gas = 750 torr = 0.99 atm (760torr=1atm)
= final pressure of gas = 1 atm (at STP)
= initial volume of gas = 8.2 L
= final volume of gas = ?
= initial temperature of gas = 
= final temperature of gas =
(at STP)
Now put all the given values in the above equation, we get:


Thus volume the gas will occupy at STP is 6.9 L
As temperature increases, kinetic energy increases.