Answer:
BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄
Explanation:
1. Calculate the equilibrium concentrations of oxalate ion
Let [C₂O₄²⁻] = c
(a) Barium oxalate
BaC₂O₄ ⇌ Ba²⁺ + C₂O₄²⁻
E/mol·L⁻¹: 5.0 × 10⁻⁵ c
Ksp = [Ba²⁺][C₂O₄²⁻] = 5.0 × 10⁻⁵c = 1.5 × 10⁻⁸
c = (1.5 × 10⁻⁸)/(5.0 × 10⁻⁵) = 3.0 × 10⁻⁴ mol·L⁻¹
(b) Zinc oxalate
ZnC₂O₄ ⇌ Zn²⁺ + C₂O₄²⁻
E/mol·L⁻¹: 2.0 × 10⁻⁷ c
Ksp = [Zn²⁺][C₂O₄²⁻] = 2.0 × 10⁻⁷c = 1.35 × 10⁻⁹
c = (1.35 × 10⁻⁹)/(2.0 × 10⁻⁷) = 6.8 × 10⁻³ mol·L⁻¹
(c) Silver oxalate
Ag₂C₂O₄ ⇌ 2Ag⁺ + C₂O₄²⁻
E/mol·L⁻¹: 3.0 × 10⁻⁵ c
Ksp = [Ag⁺]²[C₂O₄²⁻] = (3.0× 10⁻⁵)²c = 9.0 × 10⁻¹⁰c = 1.1 × 10⁻¹¹
c = (1.1 × 10⁻¹¹)/(9.0 × 10⁻¹⁰) = 0.012 mol·L⁻¹
2. Decide the order of precipitation
BaC₂O₄ will precipitate when c > 3.0 × 10⁻⁴ mol·L⁻¹
ZnC₂O₄ will precipitate when c > 6.8 × 10⁻³ mol·L⁻¹
Ag₂C₂O₄ will precipitate when c > 0.028 mol·L⁻¹
This happens to be the order of increasing concentration of oxalate ion.
The order of precipitation is
BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄
Answer:
magnesium + hydrochloric acid → hydrogen gas + magnesium chloride
explanation:
the nitrogen in HNO3 is in the +5 oxidation state and is easily reduced. The reduction would result in the oxidation of the hydrogen gas, forming the water once again.The sulfur in H2SO4 is also in its highest oxidation state, +6.
<em>Hope</em><em> this</em><em> helps</em><em> </em><em>:</em><em>)</em>
Use Charles' Law: V1/T1 = V2/T2. We assume the pressure and mass of the helium is constant. The units for temperature must be in Kelvin to use this equation (x °C = x + 273.15 K).
We want to solve for the new volume after the temperature is increased from 25 °C (298.15 K) to 55 °C (328.15 K). Since the volume and temperature of a gas at a constant pressure are directly proportional to each other, we should expect the new volume of the balloon to be greater than the initial 45 L.
Rearranging Charles' Law to solve for V2, we get V2 = V1T2/T1.
(45 L)(328.15 K)/(298.15 K) = 49.5 ≈ 50 L (if we're considering sig figs).
Answer:
Water purification is the process of removing undesirable chemicals, biological contaminants, suspended solids and gases from contaminated water. The goal is to produce water fit for a specific purpose. Most water is purified for human consumption (drinking water), but water purification may also be designed for a variety of other purposes, including meeting the requirements of medical, pharmacological, chemical and industrial applications. In general the methods used include physical processes such as filtration,sedimentation, and distillation, biological processes such as slow sand filters or biologically active carbon, chemical processes such asflocculation and chlorination and the use of electromagnetic radiation such as ultraviolet light.
Extreme lack or loss of water may lead to dehydration of the body and other health complications. For this reason, governments ensure that citizens have access to clean and safe water for domestic use. Clean water is essential in ensuring that no pathogens or impurities are ingested by people, either through direct drinking or through food.
To attain these standards of water, purification is important. Water purification involves physical and chemical processes, which are carried out stepwise to ensure the water is safe and free from any harm. This directional process essay synthesizes the steps, which have to be followed to achieve this task.
In essence, water purification denotes the process used to free water from impurities like bacteria and contaminants. Since the process is aimed at eliminating all the impurities present in the water, it is necessary to apply chemical and physical methods of separation in an orderly manner.
Explanation:
167 mL
P1V1 = P2V2
P1 = .8 atm
V1 = 250 mL
P2 = 1.2 atm
Solve for V2 —> V2 = P1V1/P2
V2 = (0.8 atm)(250 mL) / (1.2 atm) = 167 mL
