6.02 x 1023 atoms weigh out 63.55 grams copper.
No. of Molecules in water = 3.5mole x (6.02 x 10^23) molecules/mole = 2.107 x 10^24 molecules of H2O
Answer:
Bromine is a dark reddish-brown fuming liquid with a pungent odor. Denser than water and soluble in water. Hence sinks in water.
<span>The best answer among
the choices is the first option. The chemical property of soda is that it is a
highly basic substance. It's chemical name is sodium carbonate. It is more
basic than sodium bicarbonate. Adding soda ash in a solution would increase the
pH of the solution.</span>
Answer:
3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O
Explanation:
Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O
There are 3 atoms of Ba on the right side and 1atom on the left side. It can be balance by putting 3 in front of Ba(OH)2 as shown below:
3Ba(OH)2 + H3PO4 —> Ba3(PO4)2 + H2O
There are 2 atoms of P on the right side and 1atom on the left. It can be balance by putting 2 in front of H3PO4 as shown below:
3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + H2O
Now, there are a total of 12 atoms of H on the left side and 2 atoms on the right side. It can be balance by putting 6 in front of H2O as shown below:
3Ba(OH)2 + 2H3PO4 —> Ba3(PO4)2 + 6H2O
Now the equation is balanced as the numbers of the atoms of the different elements present on both sides are equal
Answer:
The density of the crystal is 10.22 g/cm³
Explanation:
Step 1: Data given
Molybdenum (Mo) has a BCC crystal structure
atomic radius = 0.1363 nm
atomic weight of 95.94 g/mol
Step 2: Calculate density of a bcc crystal
Density ρ= (nA
*Mo)/(Vc*Na)
⇒For BCC, n = 2 atoms/unit cell, and realizing that V
c = a
³
a = 4R/√3
Vc =(4R/√3)³
AMo = atomic weight = 95.94 g/mol
ρ = (n*A
Mo)/((4R/√3)³ *Na)
⇒with n = 2 atoms/unit cell
⇒ with AMo = 95.94 g/mol
⇒ with Vc =(4R/√3)³ = (4*0.1363*10-7 cm)³ /(√3)³
⇒with Na = 6.022*10^23 atoms/mol
ρ =10.22 g/cm³
The density of the crystal is 10.22 g/cm³