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boyakko [2]
2 years ago
11

Explain how particles move before during and after melting

Chemistry
2 answers:
kirill115 [55]2 years ago
6 0

Answer:

(What happens to particles during melting?)

When a solid is heated the particles gain energy and start to vibrate faster and faster the particles are still loosely connected they are able to move around. At this point the solid is melting to form a liquid The particles in the liquid are the same as in the solid but they have more energy

(particles after melting after melting?)

during melting, the particles start to move about staying close to their neighbouring particles then move more freely

Explanation:

Aleksandr-060686 [28]2 years ago
3 0

Answer:

Particles would move more freely, while still staying close together depending on the shape of the liquid

Explanation:

Melting is the process of going from a solid to a liquid due to the increase in heat/energy. This increase in heat/energy increases the speed at which the atoms within the object moves. Lets say we had an ice cube. While it is a cube, the particles inside the cube are slow and compact, staying close together.

When enough energy is gained, this makes the particles begin to move faster, gaining heat and energy which results in the ice cube melting and moving more freely than normal.

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2C6H10 + 17O2 = 12CO2 + 10H2O
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Answer:

n O2 = 2.125 mol

Explanation:

balanced reaction:

  • 2C6H10 + 17O2 → 12CO2 + 10H2O

∴ n CO2 = 1.5 mol

⇒ n O2 = (1.5 mol CO2)*(17 mol O2/12 mol CO2)

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3 years ago
How many grams of water can be formed from the reaction of 8.76 grams of H2 with 10.5 liters of O2 (at STP) according to the bal
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Answer:

16.9g of H₂O can be formed

Explanation:

Based on the chemical reaction, 2 moles of H₂ react per mole of O₂. To anser this question we must find limiting reactant converting the mass and volume of each reactant to moles:

<em>Moles H₂ -Molar mass: 2.016g/mol-:</em>

8.76g * (1mol / 2.016g) = 4.345 moles

<em>Moles O₂:</em>

PV = nRT

PV/RT = n

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V = 10.5L

R = 0.082atmL/molK

T = 273.15K at STP

n = 1atm*10.5L / 0.082atmL/molK*273.15K

n = 0.469 moles of oxygen

For a complete reaction of 4.345 moles moles of hydrogen are required:

4.345 moles H2 * (1mol O2 / 2mol H2) = 2.173 moles of O2 are required. As there are just 0.469 moles, Oxygen is limiting reactant

Now, 1 mole of O2 produce 2 moles of H2O. 0.469 moles will produce:

0.469 moles O₂ * (2 moles H₂O / 1mol O₂) = 0.938 moles H₂O.

The mass is -Molar mas H₂O = 18.01g/mol-:

0.938 moles * (18.01g/mol) =

<h3>16.9g of H₂O can be formed</h3>
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