This ultimately means that the object being tested is NEUTRAL as it is attracted to both a positive and negative charge
Answer:
it's can be detected only through the use of thermal imaging e
Answer:
Acceleration,
Explanation:
Given that,
Height from a ball falls the ground, h = 17.3 m
It is in contact with the ground for 24.0 ms before stopping.
We need to find the average acceleration the ball during the time it is in contact with the ground.
Firstly, find the velocity when it reached the ground. So,
u = initial velocity=0 m/s
a = acceleration=g
It is in negative direction, u = -18.41 m/s
Let a is average acceleration of the ball. Consider, v = and u = -18.41 m/s.
So, the average acceleration of the ball during the time it is in contact is .
Assuming the earth and the sun to be perfect spheres,
Volume of the sphere = 4/3 * pi * (r**3)
Volume of the earth = 4/3 * pi * ((4000*1.609 km)**3) = 1.116 E 12 km3
Volume of the Sun= 4/3 * pi * ((7 E 5 km)**3) = 1.436 E 18 km3
Density = mass /volume
Density of earth = 6 E 24 kg / 1.116 E 12 km3 = 5.376 E 12 [kg/km3]
Density of Sun= 2 E 30 kg / 1.436 E 18 km3 = 1.392 E 12 [kg/km3]
Density of earth / Density of Sun =
5.376 E 12 [kg/km3] / 1.392 E 12 [kg/km3] = 3.86
There is no definite end to earths atmosphere, but technically the border between the outer space and earth gets thinner as you move up from the earths surface. The Karman line is the closest definition there is which describes the end of the earth's atmosphere, it is 100 km above earth's sea level at approximately 1.56 % of total earth's radius. This describes the boundary between the outer space and the atmosphere.