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Aleksandr-060686 [28]
3 years ago
5

The velocity selector in in a mass spectrometer consists of a uniform magnetic field oriented at 90 degrees to a uniform electri

c field so that a charge particle entering the region perpendicular to both fields will experience an electric force and a magnetic force that are oppositely directed. If the uniform magnetic field has a magnitude of 37.8 ~\text{mT}37.8 mT, then calculate the magnitude of the electric field that will cause a proton entering the velocity selector at 40.640.6 km/s to be undeflected. Give your answer in units of kV/m.
Physics
1 answer:
NeTakaya3 years ago
3 0

Answer:

50k/h is the answer to iy

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Which group in the periodic table is known as salt farmers?
adell [148]
<span>Which group in the periodic table is known as salt formers?

 The correct option is the last one: Halogen family.
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5 0
3 years ago
Read 2 more answers
Gibbons, small Asian apes, move by brachiation, swinging below a handhold to move forward to the next handhold. A 9.4 kg gibbon
Katarina [22]

Answer:

upward force acting = 261.6 N

Explanation:

given,

mass of gibbon = 9.4 kg

arm length = 0.6 m

speed of the swing

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force of gravity = - mg

F_{branch}=F_{centripetal}-F_{gravity}

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7 0
3 years ago
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Tema [17]

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3 0
3 years ago
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Basile [38]

Answer:

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Solving yields:

10\cdot 14 + 12\cdot (-8)=(10+12)v_f\\\implies v_f=\boxed{2 \text{ m/s}}

4 0
2 years ago
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