Answer:
T = 99.51 hour
Explanation:
Mass of Uranus, 
The moon Umbriel orbits Uranus at a distance of 
We need to find Umbriel's orbital period. Let it is T. Using Kepler's third law of motion to find it.
As 1 hour = 3600 s
358244.51 s = 99.51 hour
Hence, Umbriel's orbital period is 99.51 hour.
First we will use the concepts of motion kinetics for which the final speed is defined as shown below,
Here,
= Final velocity
= Initial velocity
a = Acceleration
s = Distance
Replacing,
Using the conservation of energy for kinetic energy we have,
Therefore the kinetic energy of the car is 31900J
Answer:
B.
It will be greater than 10 J.
Explanation:
The total mechanical energy of an object is the sum of its potential energy (PE) and its kinetic energy (KE):
E = PE + KE
According to the law of conservation of energy, when there are no frictional forces on an object, its mechanical energy is conserved.
The potential energy PE is the energy due to the position of the object: the highest the object above the ground, the highest its PE.
The kinetic energy KE is the energy due to the motion of the object: the highest its speed, the largest its KE.
Here at the beginning, when it is at the top of the roof, the baseball has:
PE = 120 J
KE = 10 J
So the total energy is
E = 120 + 10 = 130 J
As the ball falls down, its potential energy decreases, since its height decreases; as a result, since the total energy must remain constant, its kinetic energy increases (as its speed increases).
Therefore, when the ball reaches the ground, its kinetic energy must be greater than 10 J.
Answer:
the tension of the rope is 34.95 N
Explanation:
Given;
length of the rope, L = 3 m
mass of the rope, m = 0.105 kg
frequency of the wave, f = 40 Hz
wavelength of the wave, λ = 0.79 m
Let the tension of the rope = T
The speed of the wave is given as;
Therefore, the tension of the rope is 34.95 N
