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gregori [183]
3 years ago
8

What is the area, in square inches, of the rectangle? Show your work!!

Mathematics
2 answers:
VMariaS [17]3 years ago
5 0

Answer:

Above is the solution to the question

erma4kov [3.2K]3 years ago
4 0

Answer:

\huge\boxed{\sf 7 \frac{13}{20} \ in. ^2}

Step-by-step explanation:

Length of the rectangle = \displaystyle 2 \frac{1}{4} = \frac{9}{4} \ in.

Width of the rectangle =  \displaystyle 3 \frac{2}{5} = \frac{17}{5} \ in.

<u>Area of the rectangle:</u>

= Length × Width

\displaystyle = \frac{9}{4} \times \frac{17}{5} \\\\= \frac{9 \times 17}{4 \times 5} \\\\= \frac{153}{20} \\\\= 7 \frac{13}{20} \ in.^2\\\\\rule[225]{225}{2}

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2x + 5y = 13<br> -x + 4y = 13<br> solve by elimination
emmainna [20.7K]

Answer:

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6 0
3 years ago
The area of a gymnasium is (27x + 18) square units. Factor 27x + 18 to find possible dimensions of the gymnasium.
Veronika [31]

Answer:

Dimension of gymnasium= 9 units and (3x+2) units.

Step-by-step explanation:

We have been given the area of a gymnasium is 27x+18 square units. We are asked to find possible dimensions of gymnasium by factoring our given expression for area of gymnasium.

Let us factor our greatest common factor of our given expression. We can see that 9 is the GCF of our given expression.

(9\times 3x+9\times 2)

Upon factoring out 9 from our given expression we will get,

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Therefore, the possible dimensions of the gymnasium will be 9 units and (3x+2) units as we will get the same area for gymnasium by multiplying these both dimensions.  

8 0
3 years ago
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astra-53 [7]

Step-by-step explanation:

  • 1

vector AB(3-(-6); 5-7)

vector AB(9;-2)

AB= \sqrt{9^{2}+(-2)^{2}  } = \sqrt{85}

  • 2

M is the midpoint of AB

we have B(-5;10) and M(1;7)

let A(x;y)

(x-5)/2 = 1 ⇒ x-5 = 2⇒ x = 7

(10=y)/2 = 7⇒ 10+y = 14 ⇒y= 4

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  • 3

the center of the circle is the midponit of the line joining both ends of the diameter

let A(x;y) be the other end

(-2+x)/2 = 2 ⇒ -2+x = 4⇒ x= 6

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  • 4

A,B and C are collinear such as AB=BC so b is the midpoint of AC

(-5+1)/2 = y ⇒ y = -4/2 ⇒ y = -2

((-3=x)/2 = 7 ⇒ -3+x = 14 ⇒ x = 17

so x= 17 and y = -2

7 0
3 years ago
How many triangles can be constructed with sides measuring 5 m, 16 m, and 5 m?
lianna [129]
There are two measures 5 cm then the triangle will be isosceles or 16 is far beyond 5 + 5 = 10 so we cannot build any triangle so te answer is <span>B none
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3 years ago
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Answer:

the answer is c i did the test

Step-by-step explanation:

pls i did the test trust me.

7 0
3 years ago
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