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gregori [183]
2 years ago
8

What is the area, in square inches, of the rectangle? Show your work!!

Mathematics
2 answers:
VMariaS [17]2 years ago
5 0

Answer:

Above is the solution to the question

erma4kov [3.2K]2 years ago
4 0

Answer:

\huge\boxed{\sf 7 \frac{13}{20} \ in. ^2}

Step-by-step explanation:

Length of the rectangle = \displaystyle 2 \frac{1}{4} = \frac{9}{4} \ in.

Width of the rectangle =  \displaystyle 3 \frac{2}{5} = \frac{17}{5} \ in.

<u>Area of the rectangle:</u>

= Length × Width

\displaystyle = \frac{9}{4} \times \frac{17}{5} \\\\= \frac{9 \times 17}{4 \times 5} \\\\= \frac{153}{20} \\\\= 7 \frac{13}{20} \ in.^2\\\\\rule[225]{225}{2}

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Which expression can be used to determine the average rate of change in f(x) over the interval mc001-1.jpg
Mrac [35]
The average rate of change of a function f(x) over an interval (a, b) is given by
\frac{f(b)-f(a)}{b-a}

Therefore, given a function, f(x), over an interval (2, 9), the average rate of change of the function can be found using the expression
\frac{f(9)-f(2)}{9-2}
8 0
3 years ago
Read 2 more answers
What is the product? StartFraction 3 k Over k + 1 EndFraction times StartFraction k squared minus 1 Over 3 k cubed EndFraction S
Nana76 [90]

Answer:

StartFraction negative 1 Over k cubed EndFraction

Step-by-step explanation:

3k / (k + 1) × (k²- 1) / 3k³

= 3k(k² - 1) / (k + 1)(3k³)

= 3k³ - 3k / 3k⁴ + 3k³

= -3k / 3k⁴

= -1/k³

StartFraction k + 1 Over k squared EndFraction

(k + 1) / k²

StartFraction k minus 1 Over k squared EndFraction

(k - 1)/k²

StartFraction negative 1 Over k cubed EndFraction

= -1/k³

StartFraction 1 Over k EndFraction

= 1/k

4 0
3 years ago
I need help on math on how to solve a linear equation. So how do you solve (x-2)+(2x+5).
saveliy_v [14]
So, put your "x's" together first and then your intercepts. That should answer your question :)
4 0
3 years ago
Chance can wash the car in 2 hours, while Sandy can wash the same car in 4 hours. How many hours would it take for them to wash
san4es73 [151]
<span>1 hour and 1/3rd of an hour.</span>
6 0
3 years ago
A seal went 25 feet below sea level to catch a fish. A sea lion dove 10 feet less than three times as deep as the seal to catch
vfiekz [6]

Answer:

65 feet below sea level.

Step-by-step explanation:

With the information provided, we can create the following equation for the position of the sea lion (p)

p = 3x - 10

In this equation, x would be the final position of the seal when it caught the fish. Since we are told that the seal's position is 25 feet below sea level then we can plug in this value as x and solve for p...

p = (3 * 25) - 10

p = 75 - 10

p = 65

Finally, we can see that the sea lion's position is 65 feet below sea level.

7 0
3 years ago
Read 2 more answers
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