Answer:
18 kJ
Explanation:
Given:
Initial volume of air = 0.05 m³
Initial pressure = 60 kPa
Final volume = 0.2 m³
Final pressure = 180 kPa
Now,
the Work done by air will be calculated as:
Work Done = Average pressure × Change in volume
thus,
Average pressure = 
= 120 kPa
and,
Change in volume = Final volume - Initial Volume = 0.2 - 0.05 = 0.15 m³
Therefore,
the work done = 120 × 0.15 = 18 kJ
Answer:
See the attached pictures for detailed answer.
Explanation:
See the attached pictures for step by step explanation.
Explanation:
Pressure = force/area
Pressure stays the same.
If the area is doubled the force is doubled.
Using
q = k*v,
where q = traffic flow rate, k = density, v = space mean speed.
so, 1800 = k x 40
so, k = 1800/40 = 45 veh/mie on two lanes,
so k = 45/2 = 22.5veh/h/in
