Exercises

A) Your friend is faced with a situation i n whi ch t here is a difficulty in

Arlecino [84]

The Steps my friend need to make an ethical decision are:

Step One: He or she needs to define the Problem.
Step Two: He or she needs to find out possible Resources to solve the problem and then Brainstorm on the List for the Potential Solutions to the problem.
Step Three : Evaluate and examine those Alternatives. ...
Step Four : Make his or her Decision, Implement It and then examine your Decision.

<h3>What is ethical decision model?</h3>

An ethical decision-making model is known to be a kind of a tool that can be used by a person to help create the ability to think in regards to an ethical dilemma and come to an ethical decision.

Note that Ethical decision-making is one that is dependent on the key character values such as trustworthiness, respect, role, fairness, and others.

Therefore, The Steps my friend need to make an ethical decision are:

Step One: He or she needs to define the Problem.
Step Two: He or she needs to find out possible Resources to solve the problem and then Brainstorm on the List for the Potential Solutions to the problem.
Step Three : Evaluate and examine those Alternatives. ...
Step Four : Make his or her Decision, Implement It and then examine your Decision.

Learn more about ethical decision from

brainly.com/question/21105288

#SPJ1

7 0

1 year ago

Two Carnot engines operate in series such that the heat rejected from one is the heat input to the other. The heat transfer from

kykrilka [37]

Answer:

Given:

high temperature reservoir $T_{H} =1000k$

low temperature reservoir $T_{L} =400k$

thermal efficiency $n_{1}= n_{2}$

The engines are said to operate on Carnot cycle which is totally reversible.

To find the intermediate temperature between the two engines, The thermal efficiency of the first heat engine can be defined as

$n_{1} =1-\frac{T}{T_{H} }$

The thermal efficiency of second heat engine can be written as

$n_{2} =1-\frac{T_{L} }{T}$

The temperature of intermediate reservoir can be defined as

$1-\frac{T}{T_{H} } =1-\frac{T_{L} }{T} \\T^2=T_{L} T_{H} \\T=\sqrt{T_{L} T_{H} }\\T=\sqrt{400*1000} =632k$

8 0

3 years ago

A cylindrical specimen of a hypothetical metal alloy is stressed in compression. If its original and final diameters are 30.00 a

IrinaVladis [17]

Answer:

The original length of the specimen $l_{o} = 104.7 mm$

Explanation:

Original diameter $d_{o}$ = 30 mm

Final diameter $d_{1}$ = 30.04 mm

Change in diameter Δd = 0.04 mm

Final length $l_{1}$ = 105.20 mm

Elastic modulus E = 65.5 G pa = 65.5 × $10^{3}$ M pa

Shear modulus G = 25.4 G pa = 25.4 × $10^{3}$ M pa

We know that the relation between the shear modulus & elastic modulus is given by

$G = \frac{E}{2(1 + \mu)}$

$25.5 = \frac{65.5}{2 (1 + \mu)}$

$\mu = 0.28$

This is the value of possion's ratio.

We know that the possion's ratio is given by

$\mu = \frac{\frac{0.04}{30} }{\frac{change \ in \ length}{l_{o} } }$

${\frac{change \ in \ length}{l_{o} } = \frac{\frac{0.04}{30} }{0.28}$

${\frac{change \ in \ length}{l_{o} } =$ 0.00476

$\frac{l_{1} - l_{o} }{l_{o} } = 0.00476$

$\frac{l_{1} }{l_{o} } = 1.00476$

Final length $l_{o}$ = 105.2 m

Original length

$l_{o} = \frac{105.2}{1.00476}$

$l_{o} = 104.7 mm$

This is the original length of the specimen.

5 0

3 years ago

Multiple Choice

mote1985 [20]

I think it’s manufacturing

7 0

3 years ago

The most important rating for batteries is the what

kifflom [539]

Answer:

I'm completely sure that the answer is: The most important rating for batteries is the ampere-hour rating. Ampere-hour is the battery discharge rating. It's used as a measure of charge in your device. It indicates how long your device will work without charging.

Explanation:

Hope this helped!

7 0

2 years ago