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Bad White [126]
3 years ago
12

Exercises

Engineering
1 answer:
Feliz [49]3 years ago
5 0

Answer:

Rocket

Gas

Explanation:

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Answer:

b. 2.3 kPa.

Explanation:

This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

P_{1} + \rho \cdot \frac{v_{1}^{2}}{2} = P_{2} + \rho \cdot \frac{v_{2}^{2}}{2}

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P_{1}, P_{2} - Pressures at the beginning and at the end of the current line, measured in kilopascals.

\rho - Water density, measured in kilograms per cubic meter.

v_{1}, v_{2} - Fluid velocity at the beginning and at the end of the current line, measured in meters per second.

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P_{1} - P_{2} = \rho \cdot \frac{v_{2}^{2}-v_{1}^{2}}{2}

If \rho = 1000\,\frac{kg}{m^{3}}, v_{1} = 3\,\frac{m}{s} and v_{2} = 2.1\,\frac{m}{s}, then:

P_{1} - P_{2} = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \frac{\left(2.1\,\frac{m}{s} \right)^{2}-\left(3\,\frac{m}{s} \right)^{2}}{2}

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P_{1} - P_{2} = -2.295\,kPa (1 kPa is equivalent to 1000 Pa)

Hence, the right answer is B.

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