V = 20 m/s
Ecin = 1.8 x 10^5 J
Ecin = m*v^2/ 2
1.8*10^5 = m*400/2
200m = 1.8*10^5
I know you can do it :)
#include<studio.h>
int main( )
{
int n;
int a,b,c,d,x,y;
int avarage;
printf("enter value of n:\n");
scanf("%d",&n);
printf("enter value of a:\n,b:\n,c:\n,d:\n,x:\n,y:\n);
scan f("%d\%d\n%d\n%d\n%d\n%d\n",&a,b,c,d,x,y);
sum=(a+b+c+d+x+y);
avarage=(sum/n);
print f("%d",avarage);
if
{
n=positive interger
}
else
{
printf ("n must be positive");
}
return 0;
}
That would be the independent variable.
Dependent variable changes according to the independent variable
I honestly don’t know about graphing and stable variables never heard of it before
Answer:

Negative sign shows that velocity of the car is decreases at a constant rate
Explanation:
We have given velocity of the car is decreases from 32 m /sec to 24 m/sec in 4 second
So initial velocity of the car u = 32 m /sec
And finally car reaches to a velocity of 24 m/sec
Time taken to change in velocity = 4 sec
So final velocity v = 24 m/sec
From first equation of motion v = u+at
So 

Negative sign shows that velocity of the car is decreases at a constant rate