The solution would be like
this for this specific problem:
<span>v = ? </span><span>
<span>u = 0.0 m/s </span>
<span>a = 9.8 m/s^2 </span>
<span>s = 56.1 m </span></span>
<span>v^2 = (0.0 m/s)^2 + [2 *
(9.8 m/s^2) * (56 m) ] </span><span>
<span>v^2 = 2 * (9.8 m/s^2) * (56 m) </span>
<span>v^2 = 1,097.6 m^2/s^2 </span>
<span>v = SQRT {1,097.6 m^2/s^2 } </span></span>
v = 33.1 m/s
<span>v = u + at </span>
<span>(v - u) / a = t </span>
[ (33.1 m/s) - (0.0 m/s)
] / (9.8 m/s^2) = 3.38 seconds
If the pigeon is 56.0 m below the initial position of the
falcon, it will take 3.38 seconds for the falcon to reach the pigeon. I am
hoping that this answer has satisfied your query and it will be able to help
you in your endeavor, and if you would like, feel free to ask another question.
Average speed = (distance covered) / (time to cover the distance)
= (200 miles) / (5.5 hours)
= (200/5.5) mile/hour
= 36.4 miles per hour (rounded)
Sound waves <span>can NOT travel through the vacuum of space?</span>
Answer:
Maximum height will be 
Explanation:
We have given initial velocity through which basketball is thrown 
Acceleration due to gravity 
At maximum height velocity will be zero
So final velocity v = 0 m /sec
According to third equation of motion 
( Negative sign is due to upward acceleration )

Answer:
the light emitting must be of greater wavelength
Explanation:
For this exercise we must use the Planck equation
E = h f
And the speed of light
c = λ f
f = c / λ
We replace
E = h c / λ
The wavelength of the green light is of the order of 500 nm, let's calculate the energy
E = 6.63 10⁻³⁴ 3 10⁸ /λ
E = 1,989 10⁻²⁵ /λ
λ = 500 nm = 500 10⁻⁹ m
E = 1,989 10⁻²⁵ / 500 10⁻⁹
E = 3,978 10⁻¹⁹ J
That is the energy of the transition for a transition is an intermediate state the energy must be less, this implies that the wavelength must increase. For the explicit case of a state with half of this energy
= E / 2
= 3,978 10⁻¹⁹ / 2 = 1,989 10⁻¹⁹
Let's clear and calculate
λ = h c / E
λ = 1,989 10⁻²⁵ / 1,989 10⁻¹⁹
λ = 1 10⁻⁶ m
Let's reduce to nm
λ = 1000 nm
This wavelength is in the infrared region
the light emitting must be of greater wavelength