It is very large in size, I don’t have an exact number but i believe it is over the 1,000s.
With density implying the ratio of mass per volume, the gas density<span> of the balloon, therefore, modifies only with its volume when mass is held constant. If we compress the balloon, we </span>compress the air and two things will happen<span>: the air pressure in the balloon will increase.</span>
Answer:
F = 2 [N], choose option (2)
Explanation:
The principle of impulse is defined by the following expression:
Impulse = Force * Time
Force = force acting [N] or [kg*m/s^s]
Time = time during the impulse [s]
Replacing:
Impulse = 10[kg*m/s^2] * 10 [s]
Impulse = 0,1 [kg*m/s]
Now with this impulse, we can find the force for the new time.
F = Impulse/Time
F = 0.1[kg*m/s] / 0.05[s]
F = 2 [N]
26.10 N is the vertical component of the force.
Rx represents the Horizontal component of force
Ry represents The Vertical component of force
According to the given diagram
Rx - Tcosθ = 0
Rx = Tcosθ
And,
Ry + Tsinθ = mg
Ry = mg - Tsinθ
The horizontal component of force =The Vertical component of force
Rx = Ry
Tcosθ = mg - Tsinθ
T(cosθ + sinθ) = 29 × 9.8 = 284.2 N
T√2 cosθ = 284.2 N
T × √2 ×0.544 = 284.2 N
T × 0.769 = 284.2 N
T = 370 N (app)
So,
Ry = 284.2 - 370 (sin 57°)
= 284.2 - 310.3 = -26.10 N
Hence, 26.10 N is the vertical component of the force exerted.
Learn more about the horizontal and vertical components here
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A 60-w power lightbulb uses 0.5 amps of electricity when connected to a 120-v home line.
Calculation:
Provided that,
Power, P = 60 w
Voltage, V = 120 v
We have to find out the current or electricity consumption, I.
We know that Power (P)is equal to the voltage(V) divided by current(I), or
P = VI
⇒I = P/ V [when power is divided by voltage we get current]
⇒I = 60 / 120
⇒I = 0.5 amp
Therefore from the above calculation, it is concluded that when a 60 w bulb is operating on a 120 v line, it consumes 0.5 amp current.
Learn more about power here:
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