Answer:

Explanation:
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In this case, since this acid-base neutralization is performed in a 1:2 mole ratio of acid to base as the former is a diprotic acid (two hydrogen ions in the molecule), we can write the following equation:

In such a way, we can solve for the molarity of the acid, given the molarity and concentration of the NaOH base and the volume of the acid:

Thus, we plug in the given data to obtain:

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Answer:
transfer pipet that had markings every 0.1 mL.
Explanation:
Answer:
17.3124 grams
Explanation:
Given;
Amount of heat to be produced = 175 kJ
Molar mass of the carbon monoxide = 12 + 16 = 28 grams
Now,
The standard molar enthalpy of carbon monoxide = 283 kJ/mol
Thus,
To produce 175 kJ heat, number of moles of CO required will be
= Amount heat to be produced / standard molar enthalpy of CO
or
= 175 / 283
= 0.6183
Also,
number of moles = Mass / Molar mass
therefore,
0.6183 = Mass / 28
or
Mass of the CO required = 0.6183 × 28 = 17.3124 grams
Answer:
B. it will take more energy for the particles of the solution to overcome the atmospheric pressure.
Explanation:
i checked the slideshow from educere lol (slide 8 colligative properties lesson)