441 g CaCO₃ would have to be decomposed to produce 247 g of CaO
<h3>Further explanation</h3>
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Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
mass CaO = 247 g
mol of CaO(MW=56 g/mol) :

From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

mass CaCO₃(MW=100 g/mol) :

Acid is 1. a substance that increases the hydrogen ion concentration of a solution
<span>2. removes hydroxide ions because of the tendency for H+ to combine with OH-</span>
Answer:
T₂ = 317.87 K
Explanation:
Given data:
Initial pressure = 15 atm
Final pressure = 16 atm
Initial temperature = 298 K
Final temperature = ?
Solution:
According to Gay-Lussac Law,
The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.
Mathematical relationship:
P₁/T₁ = P₂/T₂
Now we will put the values in formula:
15 atm / 298K = 16 atm/T₂
T₂ = 16atm × 298 K / 15 atm
T₂ = 4768 atm. K / 15 atm
T₂ = 317.87 K
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